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Deffense [45]
3 years ago
10

Which of the following cosine functions has a period of 3 π ?

Mathematics
2 answers:
Alinara [238K]3 years ago
7 0

Answer:

c. y= cos2/3x

Step-by-step explanation:

grin007 [14]3 years ago
5 0

ANSWER

C.

y =  \:  \cos( \frac{2}{3}x )

EXPLANATION

The period of a cosine function is calculated using the formula;

T= \frac{2 \pi}{b}

Therefore , if the period is 3π, then

\frac{2 \pi}{b}  = 3\pi

We solve b to obtain,

b =  \frac{2}{3}

This implies that, the given cosine function must have an equation of the form

y = a \:  \cos( \frac{2}{3}x )

Among the options, the function in this form is:

y =  \:  \cos( \frac{2}{3}x )

The correct choice is C.

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Initially a wheel rotating about a fixed axis at a constant angular deceleration of 0.5 rad/s 2 has an angular velocity of 0 rad
Zigmanuir [339]

Answer:

\theta = 5.83\ rad

Step-by-step explanation:

given,

angular deceleration, α = -0.5 rad/s²

final angular velocity,ω_f = 0 rad/s

angular position, θ = 6.1 rad

angular position at 3.9 s = ?

now, Calculating the initial angular speed

\omega_f^2 = \omega_i^2 + 2 \alpha \theta

0 = \omega_i^2 - 2\times 0.5\times 6.1

\omega_i = \sqrt{6.1}

\omega_i = 2.47\ rad/s

now, angular position calculation at t=3.9 s

\theta = \omega_i t + \dfrac{1}{2}\alpha t^2

\theta =2.47\times 3.9 - \dfrac{1}{2}\times 0.5\times 3.9^2

\theta = 5.83\ rad

Hence, the angular position of the wheel after 3.9 s is equal to 5.83 rad.

7 0
4 years ago
Can someone answer each step of this correctly?
Burka [1]

About Slope - Intercept Form:

  • y = mx + b
  • m is the slope
  • b is the y-intercept

About Standard Form:

  • Ax + By = C
  • A & B & C are integers
  • A & B are both non-zero
  • This form is good to use when wanting to find the x & y intercepts of a line

About Point - Slope Form:

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  • The form allows you to identify the slope & the point on the line

Other Info:

  • Remember, y comes before the x  
  • An ordered pair from your problem: (-3,1), -3 is x & 1 is y & x is before the y
  • An ordered pair from your problem: (3,5), 3 is x & 5 is y & x is before the y
  • For the graph, the vertical line is y
  • For the graph, the horizontal line is x

Hope this information helps!!! :)


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The area of a circle is 113.04 in.^2. What is the radius of the circle?
Lelechka [254]
\bf \textit{area of a circle}\\\\
A=\pi r^2\qquad 
\begin{cases}
r=radius\\
------\\
A=113.04
\end{cases}\implies 113.04=\pi r^2
\\\\\\
\cfrac{113.04}{\pi }=r^2\implies \sqrt{\cfrac{113.04}{\pi }}=r
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