Answer:
<h2><em><u>SAS</u></em><em><u> </u></em><em><u>Congruence</u></em><em><u> </u></em><em><u>Theorem</u></em><em><u> </u></em></h2>
Step-by-step explanation:
In ABC. In DEF
AB. = DE. <em>(</em><em>Given</em><em> </em><em>side</em><em>)</em>
<BAC. = <EDF. <em>(</em><em>Given</em><em> </em><em>side</em><em>)</em>
BC. = EF. <em>(</em><em>Given</em><em> </em><em>side</em><em>)</em>
<em><u>Hence</u></em><em><u>,</u></em>
Triangle ABC is congruent to Triangle DEF by<em><u> </u></em><em><u>SAS</u></em><em><u> </u></em><em><u>Congruence</u></em><em><u> </u></em><em><u>Theorem</u></em><em><u>. </u></em>
Answer:
Sarah
Step-by-step explanation:
6.75/3 is the total for one pound . This = 2,25 while calros' 4.52/2 = 2.26. sarah paid one cent less, getting a better deal than carlos
Link is scam. literally cap. don’t use it or what do ever!
Answer:
390=W 195=L Area=76050
Step-by-step explanation:
You have two lengths and one width for your perimeter
P= 2L + W
you are given your perimiter 780
780= 2L + W
To solve for your maximum Width
780-2L=w
Area is L * W
A= (780-2L)*L
A= 780L - 2L^2
the derivitive of the Area
A' = 780-4L =0
add 4L to both sides
780=4L
divide by 4 on both sides
195=L
Bring back 780-2L=W and plug in what you now know is L
780-2(195)=W
780-390=W
390=W
