Answer:

The given problem is solved using language - Python.
def f(x):
new_list=[]
for i in x:
if i%2==0:
new_list.append(i//2)
else:
new_list.append(i*2)
return new_list
my_list=list(range(1,6))
print('Original List:',my_list)
my_list=f(my_list)
print('Modified List:',my_list)

- Create a new list.
- Iterate over the list passed into the function.
- Check if the element is even or not. If true, append half the value of element in the list.
- If false, append twice the value of the element in the list.
- At last, return the new list.
There is another way of doing this - By using map() function.
—————————————————————————————
def f(x):
return list(map(lambda x:x//2 if x%2==0 else 2*x,x))
my_list=list(range(1,6))
print('Original List:',my_list)
my_list=f(2my_list)
print('Modified List:',my_list)
—————————————————————————————

Original List: [1, 2, 3, 4, 5]
Modified List: [2, 1, 6, 2, 10]
Answer:
Explanation:
The following is written in Java. It continues asking the user for inputs until they enter a -1. Then it saves all the values into an array and calculates the number of values entered, the highest, and lowest, and prints all the variables to the screen. The code was tested and the output can be seen in the attached image below.
import java.util.ArrayList;
import java.util.Arrays;
import java.util.Scanner;
class Brainly {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
int count = 0;
int highest, lowest;
ArrayList<Integer> myArr = new ArrayList<>();
while (true) {
System.out.println("Enter a number [0-10] or -1 to exit");
int num = in.nextInt();
if (num != -1) {
if ((num >= 0) && (num <= 10)) {
count+= 1;
myArr.add(num);
} else {
System.out.println("Wrong Value");
}
} else {
break;
}
}
if (myArr.size() > 3) {
highest = myArr.get(0);
lowest = myArr.get(0);
for (int x: myArr) {
if (x > highest) {
highest = x;
}
if (x < lowest) {
lowest = x;
}
}
System.out.println("Number of Elements: " + count);
System.out.println("Highest: " + highest);
System.out.println("Lowest : " + lowest);
} else {
System.out.println("Number of Elements: " + count);
System.out.println("No Highest or Lowest Elements");
}
}
}
Explanation:
These are the advantages of breaking up a single logical message into a number of fixed sized packets.
- When messages are broken into packets it increases the performance and also the reliability of the internet
- if there is an error in a single packet, this error is not going to affect the entire message.
- the efficiency of the communication line in the internet is improved.
- there is a reduction of traffic. Each packet in a single message can be transmitted through different routes.
- It reduces idleness as each packet can send from different program so each program has a service.
Here is an HTML example with the CSS class defined inline:
<!doctype html>
<html>
<head>
<style>
.YellowBackground {
background-color : yellow;
}
</style>
</head>
<body class="YellowBackground">
<h1>A yellow background</h1>
</body>
</html>