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ser-zykov [4K]
3 years ago
7

When using for loops and two-dimensional arrays, the outside loop moves across the ___________ and the inside loop moves across

the ___________.
indexes, elements

columns, rows

elements, indexes

rows, columns
Computers and Technology
1 answer:
lana66690 [7]3 years ago
6 0

Answer: rows, columns

Explanation: :)

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The amount of data that can be stored on a disk depends in part on_____.
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To what it seems like, it’s d
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Which is an effect of short-term environmental changes?
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Adaptation or death






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Explain why there is an overlap of skills and qualities in design professions​
strojnjashka [21]

The design process is the same in all creative occupations, thus, similar skills and qualities are required. The work of an architect, Craftperson, Fine Artist, or an Interior designer is to design. Whether one occupation designs clothing and associated fashions or another one designs interiors of building, they all design. Most people who work as designers possess similar personal qualities like creativity, better communication skills, and high skill set.

6 0
3 years ago
Answer the following questions:
victus00 [196]

Answer:

The answer to the following questions can be given as:

Question: 1

value of foo is = 1020

Question: 2

Output of the code is = false

Question: 3

function add(a, b)

{

 return a && b ? a + b : function (c) { return a + c; };

}

var a=add(2,5);

var x=add(2)(5);

print(a);

print(x);

output:  

7

7

Question: 4

"goh angasal a m'i"

Question: 5

In this we check that if in the window a foo function exists. otherwise we set windows.foo to bar.

Question: 6

first alert shows the value "Hello World";

second alert shows value ReferenceError, In this bar not defined.

Question: 7

The value of foo.length is  2

Question: 8

The value of foo.x is undefined

Question: 9

Function print = "one", "three", "two" .

Question :10

It is difficult to define because doSomethingElse() function is not defined.

Explanation:

In question 1 the value of the foo variable is 1020 because we perform the string concat operation.

In question 2 Output of the code is false because float value keeps in binary and when we convert 0.1 or 0.2 to binary so it is not the same.

In question 3 the output of both functions is 7.

In question 4 the output is goh angasal a m'i because In this code we use the reverse() function, split() function and join() function. Reverse function reverses the value. split function splits the value and join function join all the value of the string in a line.

In question 5 we check the value.

In question 6, the first output is Hello World and second is ReferenceError.

In question 7, the value of foo.length is 2 because this foo array we insert only 2 values.

In question 8, the value of foo.x is undefined because in the variable we reset the value of foo all together, so foo.x value is undefined.

In the question 9 function print "one",  

"three",  

"two" because In the function first, we print the message that is "one" then we define a function in this function we print the value  

"two" but before creating object we call the "three" so the print value is "one",  

"three",  

"two".

In question 10 function, the output of this function is undefined.

3 0
3 years ago
Given the following method definitions: void mystery(double a) { System.out.print("double! "); } void mystery(int a) { System.ou
kicyunya [14]

Answer:

The correct answer to the following question is option "b".  

Explanation:

The method having the same name but the arguments have different so it is called method overloading. It is a part of the object-oriented programming language (oops).  

  • In the given code we define same method two times that is "mystery()". but in this method, we pass two different parameters. For the first time, we pass a double variable that is "a" as a parameter. In the second time, we pass an integer variable that is "a" as a parameter and in both functions, we write some codes.
  • In the calling time, we call function two times. In first time calling we pass an integer value that is "1" and second time calling we pass double value that is "1.0". So the output of this code is "int! double!".  

That's why the option "b" is correct.

6 0
3 years ago
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