Doesn't look like there are any..
Answer:
Java code is given below
Explanation:
import java.util.Random;
class Die{
private int sides;
public Die(){
sides = 6;
}
public Die(int s){
sides = s;
}
public int Roll(){
Random r = new Random();
return r.nextInt(6)+1;
}
}
class DieRoll{
public static void main(String[] args) {
Die die = new Die();
int arr[] = new int[6];
for(int i=0; i<6; i++)
arr[i] = 0;
for(int i=0; i<100; i++){
int r = die.Roll();
arr[r-1]++;
}
for(int i=0; i<6; i++)
System.out.println((i+1)+" was rolled "+arr[i]+" times.");
}
}
Change the line in word, it basically returns
Answer:
Follows are the solution to these question:
Explanation:
A simple gullible algorithm is present. Let h mark the house to the left. Then we put a base station about 4 kilometers to the right. Now delete and repeat all the houses protected by this base station. In this algorithm, they can simply be seen to position baselines at b1, . . , bk as well as other algorithms (which may be an optimum algorithm) at and so on. (from left to right) That's why .