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IrinaK [193]
3 years ago
15

ASSESSMENTEVIDENCE

Physics
1 answer:
antoniya [11.8K]3 years ago
3 0

Answer:

eww jhjikiijuoujio hiuoiuoiojuoihyoi yiouyioiy

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What's the name of the compound Kl?
Nat2105 [25]

Answer: Potassium iodide

Explanation: their you go

3 0
3 years ago
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Will the 79 kg skier in the figure below slide down if f the coefficient of static friction is 0.25?
mariarad [96]

Answer:

Man will not slide down

Explanation:

Given:

Coefficient of static friction = 0.25

Angle = 13°

Computation:

Man will slide down if

tan13° > Coefficient of static friction

Tan 13 = 0.23

So,

0.23 < 0.25

So,

Man will not slide down

4 0
3 years ago
.Roshan applied a force of 144 N to the side of a cube-shaped wooden block to slide it away from himself . Assuming that he appl
ExtremeBDS [4]
  • side of cube=4cm

Area=side^2=4^2=16cm^2=0.0016m^2

  • Force=144N

\\ \sf\longmapsto Pressure=\dfrac{Force}{Area}

\\ \sf\longmapsto Pressure=\dfrac{144}{0.0016}

\\ \sf\longmapsto Pressure=90000Pa

3 0
3 years ago
Convert the following 35 cm = meters
Rufina [12.5K]

Hi, there. When converting metric units, be sure to think about the memory aid:

King (kilo) * 1000

Henry (hecto) * 100

Died (deca/deka) * 10

Unusually (unit)

Drinking (deci) \frac{1}{10}

Chocolate (centi) \frac{1}{100}

Milk (milli) \frac{1}{1000}

So 35cm = 0.35m

Explanation: This is because meters and centimeters are two place values apart. A centimeter is \frac{1}{100} of a meter.

Another useful way of remembering:

Imagine that the units of measurement and their numbers are two blocks sitting on each end of a scale. One of the blocks on each side is bigger, and the other is smaller. There has to be one big block and one small block for it to balance. Since we know a meter is larger than a centimeter, the meter is the big block on one side, and the centimeter is the small one on the other side. This means that the amount of meters cannot exceed 35, or the scale won't balance.

Hope this helped.

6 0
4 years ago
Read 2 more answers
A helicopter lifts a 81 kg astronaut 19 m vertically from the ocean by means of a cable. The acceleration of the astronaut is g/
nexus9112 [7]

Answer:

a) The work done on the astronaut by the force from the helicopter is W_{h}=16087.68\ J.

b) The work done on the astronaut by the gravitational force is  W_{g}=-15082.2\ J .

Explanation:

We are told that the mass of the astronaut is m=81\ kg, the displacement is \Delta x=19\ m, the acceleration of the astronaut is  |\vec{a}|=\frac{g}{15}  and the acceleration of gravity is g=9.8\ \frac{m}{s^{2}} .

We suppose that in the vertical direction the force from the helicopter F_{h} is upwards and the gravitational force F_{g} is downwards. From the sum of forces we can get the value of F_{h}:

                                               F_{h}-F_{g}=m.a

                                              F_{h}-mg=m.\frac{g}{15}

                                              F_{h}=mg(1+\frac{1}{15})

                              F_{h}=(\frac{16}{15}).81\ kg.\ 9.8\ \frac{m}{s^{2}}\ \Longrightarrow\ F_{h}=846.72\ N

We define work as the product of the force, the displacement of the body and the cosine of the angle \theta between the direction of the force and the displacement of the body:

                                                 W=F.\Delta x.\ cos(\theta)

a) The work done on the astronaut by the force from the helicopter

                                                  W_{h}=F_{h}.\Delta x

                                             W_{h}=846.72\ N.\ 19\ m

                                                  W_{h}=16087.68\ J

b) The work done on the astronaut by the gravitational force

                                                   W_{g}=-F_{g}.\Delta x

                                                    W_{g}=-mg\Delta x

                                            W_{g}=-81\ kg.\ 9.8\ \frac{m}{s^{2}}.\ 19\ m

                                                  W_{g}=-15082.2\ J

                                             

                                                 

                                               

                                       

5 0
3 years ago
Read 2 more answers
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