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makvit [3.9K]
2 years ago
6

A generator coil is rotated one quarter of a full revolution, from θ = 0° to θ = 90°,

Physics
1 answer:
IgorLugansk [536]2 years ago
6 0

The maximum electromotive force induced in the coil by the generator is 56.45 V.

<h3>Maximum electromotive force induced in the coil</h3>

emf(max) = NAB/t

where;

  • N is number of turns
  • A is area
  • B is magnetic field
  • t is time

Substitute the given parameter and solve for maximum electromotive force induced in the coil.

Area of the loop = 0.0462 m x 0.0462 m = 0.00213 m²

emf(max) = (353 x 0.00213 x 0.991) / (13.2 x 10⁻³)

emf(max) = 56.45 V

Thus, the maximum electromotive force induced in the coil by the generator is 56.45 V.

Learn more about electromotive force here: brainly.com/question/24158806

#SPJ1

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I=\frac{V}{R}

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The problem says that the battery is replaced with one with lower emf. Looking at the formula, this means that V decreases: if we want to keep the same brightness, we need to keep I constant, therefore we need to decrease R, the resistance of the lamp.

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Looking at this pattern, it is obvious this digits are in base 5 because once we count to 4 in a unit, we move to the next at 1.

Thus,at Mady's 2010th step, we'll convert to base 5,thus 2010 in base 5 is calculated as;

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So 2010 in base 10 is 31020 in base 5. Thus,the number of balls in the box at 2010th step is equal to 3 + 1 + 0 + 2 + 0 = 6balls

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