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makvit [3.9K]
2 years ago
6

A generator coil is rotated one quarter of a full revolution, from θ = 0° to θ = 90°,

Physics
1 answer:
IgorLugansk [536]2 years ago
6 0

The maximum electromotive force induced in the coil by the generator is 56.45 V.

<h3>Maximum electromotive force induced in the coil</h3>

emf(max) = NAB/t

where;

  • N is number of turns
  • A is area
  • B is magnetic field
  • t is time

Substitute the given parameter and solve for maximum electromotive force induced in the coil.

Area of the loop = 0.0462 m x 0.0462 m = 0.00213 m²

emf(max) = (353 x 0.00213 x 0.991) / (13.2 x 10⁻³)

emf(max) = 56.45 V

Thus, the maximum electromotive force induced in the coil by the generator is 56.45 V.

Learn more about electromotive force here: brainly.com/question/24158806

#SPJ1

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The maximum pressure variations the human ear can withstand are about how much above and below atmospheric pressure?
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4 0
4 years ago
considere que o calor específico de um material presente nas cinzas seja c=0,8j/gc. Supondo que esse material entre na turbina a
drek231 [11]

Answer:

3120J

Explanation:

Given parameters:

C  = Specific heat capacity  = 0.8J/g°C

Initial temperature  = 20°C

Mass given   = 5g

Final temperature  = 800°C

Unknown:

Energy given to the mass  = ?

Solution:

To find the energy given to the mass, let us simply use the expression below:

          H   =   m   c   ΔT

H is the unknown, the energy supplied

m is the mass of the substance

c is the specific heat capacity

ΔT is the change in temperature

Input the variables;

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3 years ago
A 160.-kilogram space vehicle is traveling along a straight line at a constant speed of 800. Meters per second. The magnitude of
natulia [17]

Answer:

Zero

Explanation:

As force acting on the body is equal to the product of mass and acceleration.

Acceleration is equal to rate of change in velocity.

Here velocity is constant so acceleration is zero.

It means the net force acting on the vehicle is zero.

4 0
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Mama L [17]

Evidence: Data gathered

Experiment: Looking through a telescope

Observations: Testing what happens

Reasoning: Thinking a problem through

I believe that these should be correct.

Hoping you pass!

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If at 10m above the ground an object has 50J of Kinetic Energy, with 50J of Potential Energy. How high can the object travel?
steposvetlana [31]

Hi there!

\large\boxed{\text{B) 20 meters}}

We know that:

E_T = U + K

U = Potential Energy (J)

K = Kinetic Energy (J)

E = Total Energy (J)

At 10m, the total amount of energy is equivalent to:

U + K = 50 + 50 = 100 J

To find the highest point the object can travel, K = 0 J and U is at a maximum of 100 J, so:

100J = mgh

We know at 10m U = 50J, so we can solve for mass. Let g = 10 m/s².

50J = 10(10)m

m = 1/2 kg

Now, solve for height given that E = 100 J:

100J = 1/2(10)h

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<u>h = 20 meters</u>

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