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Greeley [361]
3 years ago
7

If a bank offers an annual interest rate for the money in your checking account but pays interest monthly that is the annual int

erest divided by what
Mathematics
1 answer:
Art [367]3 years ago
8 0
There are 12 months in a year.... so divide apr by 12....
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M-n÷4<br><img src="https://tex.z-dn.net/?f=m%20-%20n%20%5Cdiv4" id="TexFormula1" title="m - n \div4" alt="m - n \div4" align="ab
igor_vitrenko [27]

The expression you have is already in its simplest form. However, there is another way to write it.

m - n/4

This expression is the same as the original, apart from the fact that we wrote the division as a fraction.

4 0
3 years ago
<img src="https://tex.z-dn.net/?f=f%28x%29%20%3D%20%5Cfrac%7Bx%5E%7B2%7D-x-2%20%7D%7Bx-5%7D" id="TexFormula1" title="f(x) = \fra
Umnica [9.8K]

The given function is

f(x)=\frac{x^2-x-2}{x-5}

i) We factor the numerator to obtain;

f(x)=\frac{(x-2)(x+1)}{x-5}

The vertical asymptote is where the denominator is zero.

V.A: x=5

ii) The roots are the zeros of the numerator;

Roots:

x^2-x-2=0

(x-2)(x+1)=0

x=2,x=-1

iii) At y-intercept x=0.

Put x=0 into the function and solve.

f(0)=\frac{0^2-0-2}{0-5}

f(0)=\frac{-2}{-5}

f(0)=\frac{2}{5}

Y-int: \frac{2}{5}

iv) Horizontal asymptote.

This is an improper rational function.

It has no horizontal asymptote.

v) Holes:

The given rational function has no common factors in both the numerator and the denominator.

Therefore the function has no holes.

6) For oblique Assymptote, we divide using lond division or synthetic division;

     1   -1    -2

5|  <u>      5   20</u>

     1    4    18

The quotient is x+4

The  oblique asymptote is

y=x+4

6 0
3 years ago
I guessed it prob not right but the question is how much money does Darius have at the end of the first 6 months including inter
lys-0071 [83]
Use the compound interest formula

A = P (1 + r/n)^(nt).

Here A = unknown; B = initial amount = $300;
r = rate = 0.0218; n = 2 (2 compounding periods per year); and t = 1/2 (year).

Then A = $300 (1+0.0218/2)^(2*[1/2])
           A = $300 (1.0218)^1         or       A = $300(1.0218)   =   $306.54
4 0
3 years ago
in a box of 12 fuses, there are 3 that are defective. if a quality control engineer tests 4 of these fuses at random, what is th
vladimir1956 [14]
3/12, or 1/4, are defective.
he tests 4/12, or 1/3, fuses.
1/4(1/3) = 1/12 ?

i’m sorry if this is wrong. i’m not good at probability!
6 0
3 years ago
Amy and Laura recorded the average gas mileage of their vehicles each week for four weeks. What can we concluded about the relat
Assoli18 [71]

there is no table shown

4 0
3 years ago
Read 2 more answers
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