The quotient of the fraction n³ / (2n - 6) ÷ n³ / (3n - 9) is 2/3
<h3 /><h3>How to solve fraction</h3><h3 />
n³ / (2n - 6) ÷ n³ / (3n - 9)
- multiply by the reciprocal of n³ / (3n - 9)
= n³ / (2n - 6) × 1 / n³ / (3n - 9)
= 2n - 6 / 3n - 9
= 2(n - 3) / 3(n - 3)
= 2/3
Therefore, quotient of the fraction n³ / (2n - 6) ÷ n³ / (3n - 9) is 2/3
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Answer:
30 < m
The solution would be (30, ∞)
Explanation:
For company A:
The charge is: $96 for any number of mileage ..............> I
For company B:
The charge is $75 fixed and 0.7 for each mileage m. This means that the charge is: 75 + 0.7m .................> II
We want the charge of company A to be less than the charge of company B. This means that we want I to be less than II.
Therefore,
96 < 75 + 0.7m
96 - 75 < 0.7m
21 < 0.7m
21/0.7 < m
30 < m
This means that for any mileage greater than 30, the charge of company A will be less than the charge of company B
Hope this helps :)
Answer:
108
Step-by-step explanation:
150x0.72=108
Answer:
y=4x
Step-by-step explanation:
