The derivative of f(x) at x=3 is 2x=6 approaching from the left side (apply power rule to y=x^2). The derivative of f(x) at x=3 is m approaching from the right side. In order for the function to be differentiable, the limit of derivative at x=3 must be the same approaching from both sides, so m=6. Then, x^2=mx+b at x=3, plug in m=6, 9=18+b, so b=-9.
Answers 3 and 4! since there is a negative power, that’s the only time the 0’s are added to the front :)
Answer:
The zeros are x=0,x=8
Step-by-step explanation:
f(x)=x(x-8)
To find the zeros, we set the equation equal to zero
0 = x(x-8)
Using the zero product property
x= 0 x-8=0
x=0 x=8
The zeros are 0,8
Answer:
1. False
2. True
3. True
Step-by-step explanation:
Remark
The point of this question is to encourage you to make use of your calculator. Every calculator can find square roots as far as I know.
Givens
= 8.367
= 8.49
= 8.77
One
Point A is roughly 8.15. The square root of 70 is over 8.3 So square root 70 is to the right of point A. False.
Two
Square root 72 is 8.49. B is 8.3 and C is 8.6. The statement is True
Three
sqrt(77) = 8.77. Point D is 8.75. The answer is true, but I wouldn't want to bet money on it. The difference is slightly less than 2 100s.