Answer:
0ft and 60ft
Step-by-step explanation:
Given
The attached function
Required
Determine the valid values of the domain of the function
To do this, we simply consider the starting point and the end point of the trajectory on the x-axis (i.e. the horizontal distance).
From the attached graph, the horizontal distance starts from 0 and ends at 180.
This implies that the domain is: 
From the options, the values that fall in this bracket are 0ft and 60ft
You can find the numerical part of the answer because it is the same on the right side.
For example:
¹ <<==== Regrouped
89
+
67
---------
146 <<=== I had to press space so I could position it.
So that also happens in subtraction, the left side can be found by doing the same steps in the right column.
For example:
67
- <<=== this time there was no regrouping
12
-------
55
Given:
The equation is:

To find:
The value of a.
Solution:
We have,

On simplification, we get




On comparing both sides, we get




And,




Therefore, the value of a is 2.
Answer:
Sarah is 4 ft tall.
Step-by-step explanation:
231÷84= 2.75
11 ft ÷ 2.75 = <u>4 ft</u>
Answer:
y= -1+- i √79/4
Step-by-step explanation: Here is the answer ^^