Answer:
B. h=2A/(b1+b2) . . . . parentheses are needed
Step-by-step explanation:
Multiply the equation by the inverse of the coefficient of h. That coefficient is (b1 +b2)/2, so its inverse is 2/(b1 +b2). Parentheses are needed.
... 2A/(b1 +b2) = h
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<em>Comment on the answer choices</em>
As written, <em>none of them are correct</em>. The denominator can only be written without parentheses if the division bar is horizontal, and so serves also as a grouping symbol.
Answer:
y = - 2x + 12
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Here m = - 2, thus
y = - 2x + c ← is the partial equation
To find c substitute (5, 2) into the partial equation
2 = - 10 + c ⇒ c = 2 + 10 = 12
y = - 2x + 12 ← equation of line
Answer:
Let x= number of games bowled.
Amount spent at Vista Bowl=2+3.5x
Amount spent at Pinz Bowl=5+3.25x
Setting these two equations equal to each other and solving for x will give you the number of games you can bowl to make the cost the same:
2+3.5x=5+3.25x setting equations equal
3.5x-3.25x=5-2 combining like terms
0.25x=3 simplify
(1/4)x=3 changing decimal into a fraction
x=(3)(4) multiply both sides by 4 to isolate the x
x=12 answer
Step-by-step explanation:
Answer: 3 1/3
Step-by-step explanation:
Turned into mixed numbers: -7/3 + 17/3
Multiply all the numbers by 3: -7 * 3 = -21
17 * 3 = 51
3 * 3 = 9
-21 + 51 = 30
30/9
30/9 = 3 1/3
Answer:
The value is 
Step-by-step explanation:
From the question we are told that
The amount charge per year is 
The number of members it will have at this amount is 
The amount amount increase that will lead to the loss of a single member is 
Generally the total amount the club would obtain from its members is mathematically represented as
Now let x denote the number of member lost
Hence
=> 
=> 
Thus the number of members that be removed to give the maximum income from dues is obtained by differentiating the above equation and equating it to zero
=> 
So from we have
So the amount the club should charge is
