Solve for X. Please!!
1 answer:
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For part (a), you have
If
, then 
.
If
, then 
.
So,
For part (b), since the degrees of the numerator and denominator are the same, you first need to find the quotient and remainder upon division.
In the remainder term, the denominator
can't be factorized into linear components with real coefficients, since the discriminant is negative 
. However, you can still factorized over the complex numbers, so a partial fraction decomposition in terms of complexes does exist.
Then you have
When
, you have
When
, you have
So, you could write
but that may or may not be considered acceptable by that webpage.
If
If
So,
For part (b), since the degrees of the numerator and denominator are the same, you first need to find the quotient and remainder upon division.
In the remainder term, the denominator
Then you have
When
When
So, you could write
but that may or may not be considered acceptable by that webpage.
Answer:
6 ft.
Step-by-step explanation:
Answer:
See explanation
Step-by-step explanation:
1. - given
2. - definition of midpoint (the midpoint of the segment divides the segment into two congruent segments)
3. - corresponding angles theorem (corresponding angles theorem states: If two parallel lines are cut by a transversal, then the pairs of corresponding angles are congruent.)
4. - SAS (SAS postulate states that if two sides and the included angle of one triangle are congruent to two sides and the included angle of another triangle, then these two triangles are congruent).