If the hypotenuse is 41 inches and one of the legs is 40 inches, what is the length of the other leg in inches

Your Parents give you $35 for a scooter that costs at least $100. Write and solve an inequality to find out how much money you h

pochemuha

35=M
100=C
Money needed= N

C-M=N

100-35=n

65=n

6 0

2 years ago

Al's Awesome Autos advertised a special sale on cars - Dealer cost plus 5%!! Jack and Margaret ought a luxury sedan for $23,727.

Alex17521 [72]

105/23727.90=100/x
105x=23727.90x100
105x=2372790
(105x)/105=2372790/105
x=22598

dealers cost is $22,598

the 105% is the 100% price of the car plus the 5% of that tax or whatever it is

5 0

3 years ago

A veterinary researcher takes a random sample of 60 horses presenting with colic. The average age of the random sample of horses

Licemer1 [7]

Answer:

Probability that a sample mean is 12 or larger for a sample from the horse population is 0.0262.

Step-by-step explanation:

We are given that a veterinary researcher takes a random sample of 60 horses presenting with colic. The average age of the random sample of horses with colic is 12 years. The average age of all horses seen at the veterinary clinic was determined to be 10 years. The researcher also determined that the standard deviation of all horses coming to the veterinary clinic is 8 years.

So, firstly according to Central limit theorem the z score probability distribution for sample means is given by;

Z = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = average age of the random sample of horses with colic = 12 yrs

$\mu$ = average age of all horses seen at the veterinary clinic = 10 yrs

$\sigma$ = standard deviation of all horses coming to the veterinary clinic = 8 yrs

n = sample of horses = 60

So, probability that a sample mean is 12 or larger for a sample from the horse population is given by = P( $\bar X$ $\geq$ 12)

P( $\bar X$ $\geq$ 12) = P( $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ $\geq$ $\frac{12-10}{\frac{8}{\sqrt{60} } }$ ) = P(Z $\geq$ 1.94) = 1 - P(Z < 1.94)

= 1 - 0.97381 = 0.0262

Therefore, probability that a sample mean is 12 or larger for a sample from the horse population is 0.0262.

4 0

2 years ago

For every 15 minutes of a show, there are two minutes to commercial. At this rate, if leila has seen 45 minutes of a show, how m

Ainat [17]

Answer:

51 minutes.

Step-by-step explanation:

We have been given that for every 15 minutes of a show, there are two minutes to commercial. At this rate, Leila has seen 45 minutes of a show. We are asked to find the time for which Leila has been watching TV.

We will use proportions to solve our given problem.

$\frac{\text{Minutes of TV show + Advertisement}}{\text{Minutes of TV show}}=\frac{15+2}{15}$