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3 years ago

If the hypotenuse is 41 inches and one of the legs is 40 inches, what is the length of the other leg in inches

Mathematics

1 answer:

timama [110]3 years ago

7 0

9 inches
a^2=b^2+c^2
a=41 inches
b=40 inches

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5)Write an algebraic equation for each statement, and then SOLVE for x

Andrei [34K]

Answer:

Step-by-step explanation:

1. x+6=14

14-6=8

x=8

2. 15/x=3

15/3=x

x=5

3. 7*x=56

56/7=8

x=8

4. x^2-4=12

x=4, x=-4

5. 1/4x=10

x/4 = 10

x = 40

6. 3x-9=18

x=9

7. 1/2x-10=14

x/2-10=14

x=48

8.x/8=9

8*9=72

x=72

9.2x+3=24

2x=21

x=21/2

10.20*x=140

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8 0

3 years ago

A lady is 5 years younger to her husband and he is 5 times as old as his daughter. If the daughter was 5 years old 3 years back,

adoni [48]

Answer:

Step-by-step explanation:

5x (5+3)=40-5=35

3 0

3 years ago

Pls help help help psl

sergejj [24]

Answer:

IF TWO VALUES ARE PROPORTIONAL THEY CAN BE CONNECTED IN TERMS OF k BY MAKING THEM IN A STUCTURE OF AN EQAUTION LIKE GIVEN BELOW. HERE AS THE PROPORTIONAL VALUES ARE RADIUS AND CIRCUMFERENCE WE USE THE GIVEN VALUES AND CREATE EQAUTION LIKE BELOW

r=kC

⇒WE CAN TRASNPOSE THIS TO GET

kC/r=0

⇒C/r=1/k

RECIPROCATE IT TO GET

⇒r/C=k

Maybe this will be correct answer

4 0

3 years ago

Read 2 more answers

A particle moves on a straight line and has acceleration a(t)=24t+2. Its position at time t=0 is s(0)=3 and its velocity at time

user100 [1]

Answer:

It's position at time t = 5 is 593.

Step-by-step explanation:

The velocity v(t) is the integral of the acceleration a(t)

The position s(t) is the integral of the velocity v(t)

We have that:

The acceleration is:

$a(t) = 24t + 2$

Velocity:

$v(t) = \int {a(t)} \, dt = \int {24t + 2} \, dt = 12t^{2} + 2t + K$

K is the initial velocity, that is v(0). Since V(0) = 13, K = 13

Then

$v(t) = 12t^{2} + 2t + 13$

Position:

$s(t) = \int {s(t)} \, dt = \int {12t^{2} + 2t + 13} \, dt = 4t^{3} + t^{2} + 13t + K$

Since s(0) = 3

$s(t) = 4t^{3} + t^{2} + 13t + 3$

What is its position at time t=5?

This is s(5).

$s(t) = 4t^{3} + t^{2} + 13t + 3$

$s(5) = 4*5^{3} + 5^{2} + 13*5 + 3$

$s(5) = 593$

It's position at time t = 5 is 593.

3 0

3 years ago

How many days will it take for a sum of $4,000 to earn $80 interest if it is deposited in a bank paying ordinary simple interest

Maksim231197 [3]

Answer:

It will take 146 days to earn an interest of $80.

Step-by-step explanation:

The simple interest formula is:

$I=\frac{P\times r\times t}{100}$

It is provided that:

I = $80

P = $4,000

r = 5% p.a.

Compute the time required as follows:

$I=\frac{P\times r\times t}{100}$

$t=\frac{I\times 100}{P\times r}$

$=\frac{80\times 100}{4000\times 5}\\\\=0.4\ \years\\\\=0.4\times 365\ days\\\\=146\ days$

Thus, it will take 146 days to earn an interest of $80.

4 0

3 years ago