Answer:
Behavioral modality of measurement
Step-by-step explanation:
Observing a 3rd grade student for 30 minutes as to how many time he leaves his seat without permission is a clear example of using behavioral modality of measurement.
In this modality of measurement the behavior of the object or system is observed when it is put into action.
This example shows as to what will happen or what is supposed to take place when a 3rd grade student is is seated and observed for 30 minutes. It counts as to how many times he leaves his seat in reaction to his stimulus from the environment.
Generally speaking, the number of solutions to an algebraic equation is equal to the exponent of the highest power. so the answer is b.4
Answer:
= -√6
Step-by-step explanation:
1) collect like terms by subtracting coefficients:
3√6 - 4√6
(3-4)√6
2) calculate (3-4):
(3-4)√6
-1√6
3) the coefficient of -1 does not have to be written, but the negative sign remains:
-1√6
-√6
so therefore:
-√6 is your answer
Answer: 120cm
Step-by-step explanation i took the test
Answer:
Q(t) = Q_o*e^(-0.000120968*t)
Step-by-step explanation:
Given:
- The ODE of the life of Carbon-14:
Q' = -r*Q
- The initial conditions Q(0) = Q_o
- Carbon isotope reaches its half life in t = 5730 yrs
Find:
The expression for Q(t).
Solution:
- Assuming Q(t) satisfies:
Q' = -r*Q
- Separate variables:
dQ / Q = -r .dt
- Integrate both sides:
Ln(Q) = -r*t + C
- Make the relation for Q:
Q = C*e^(-r*t)
- Using initial conditions given:
Q(0) = Q_o
Q_o = C*e^(-r*0)
C = Q_o
- The relation is:
Q(t) = Q_o*e^(-r*t)
- We are also given that the half life of carbon is t = 5730 years:
Q_o / 2 = Q_o*e^(-5730*r)
-Ln(0.5) = 5730*r
r = -Ln(0.5)/5730
r = 0.000120968
- Hence, our expression for Q(t) would be:
Q(t) = Q_o*e^(-0.000120968*t)
