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Minchanka [31]
3 years ago
12

When 5 is added to a number n, the result is greater than 11. Which inequality can be used

Mathematics
1 answer:
Basile [38]3 years ago
3 0

9514 1404 393

Answer:

  n + 5 > 11

Step-by-step explanation:

When 5 is added to a number n, the expression representing that sum is ...

  5 + n

When that is greater than 11, the expression representing that comparison is ...

  5 + n > 11

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Simplify: –3y 2x – 10y – 5x 2y <br> a. –11y – 3x <br> b. –15y 3x <br> c. –15y – 3x <br> d. –11y 7x
hoa [83]
The answer is A.<span>–11y – 3x</span>
5 0
3 years ago
Kat runs 3 1/2 miles in 3/4 of an hour. What is her unit rate? Use fractions to find out and express your answer as a mixed numb
Drupady [299]

Answer:

This is a fraction equal to

30 miles ÷ 2.5 hours

We want a unit rate where

1 is in the denominator,

so we divide top and bottom by 2.5

30 miles ÷ 2.5

2.5 hours ÷ 2.5

=

12 miles

1 hour = 12 miles hour = 12 miles per hour

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Simplify 3x²y³ over 12x⁶y
Svetllana [295]

Answer:

12x^6y

Step-by-step explanation:

7 0
3 years ago
Please help solve for x..
aalyn [17]

Answer:

x = 1 or x = -1

Step-by-step explanation:

Given equation:

x^{100}-4^x \cdot x^{98}-x^2+4^x=0

Factor out -1:

\implies -1(-x^{100}+4^x \cdot x^{98}+x^2-4^x)=0

Divide both sides by -1:

\implies -x^{100}+4^x \cdot x^{98}+x^2-4^x=0

Rearrange the terms:

\implies 4^x \cdot x^{98}-4^x-x^{100}+x^2=0

\textsf{Apply exponent rule} \quad a^{b+c}=a^b \cdot a^c \quad \textsf{to }x^{100}:

\implies 4^x \cdot x^{98}-4^x-x^{98}x^2+x^2=0

Factor the first two terms and the last two terms separately:

\implies 4^x(x^{98}-1)-x^2(x^{98}-1)=0

Factor out the common term (x^{98}-1) :

\implies (4^x-x^2)(x^{98}-1)=0

<u>Zero Product Property</u>:  If a ⋅ b = 0 then either a = 0 or b = 0 (or both).

Using the <u>Zero Product Property</u>, set each factor equal to zero and solve for x (if possible):

\begin{aligned}x^{98}-1 & = 0 & \quad \textsf{or} \quad \quad4^x-x^2 & = 0 \\x^{98} & =1 & 4^x & = x^2 \\x & = 1, -1 & \textsf{no}& \textsf{ solutions for } x \in \mathbb{R}\end{aligned}

Therefore, the solutions to the given equation are: x = 1 or x = -1

Learn more here:

brainly.com/question/27751281

brainly.com/question/21186424

3 0
1 year ago
Find the length of the hypotenuse of this right angle
zvonat [6]

c^2 = 5^2 + 8^2 = 25 + 64 = 89

c = √89

Answer: c

4 0
3 years ago
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