Answer:
y = 3x + 3
Step-by-step explanation:
y = mx + b where m= slope and b= y-intercept
the y-intercept is the point where x=0 or where the line crosses the y-axis.
This happens at (0,3) on the graph, so the y-intercept, or b, is equal to 3.
for m, slope can be defined as rise/run. So starting from a point you are given on the graph (-1,-2), count the number of spaces up you rise and how many you must go over (run) to get to the next point (0,3)
if you count, you should rise from (-1,-2) 5 spaces and move to the right (run) 1 space to get to (0,3).
rise/run = 3/1
3/1 = 3
the slope is 3.
now that you have the slope and the y-intercept, you can just plug it into the equation
y = 3x + 3
The inverse of matrix A =
is
The given matrix is A = ![\left[\begin{array}{cc}2&2&1&3\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D2%262%261%263%5C%5C%5Cend%7Barray%7D%5Cright%5D)
The inverse of a matrix is given by
...(1)
Now, determinant of matrix A is
|A| = 
= (3)(2) - (2)(1)
= 6 - 2
= 4
Now, adjoint A will be
= 3
= -1
= -2
= 2
AdjA = 
Now, substituting the values of |A| and AdjA in equation (1), we get
Therefore,
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