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mylen [45]
3 years ago
8

P(x)=5x^2-3x+7(x=1) Pls

Mathematics
1 answer:
kramer3 years ago
4 0

Answer:

9

Step-by-step explanation:

Given

p(x) = 5x² - 3x + 7 ← substitute x = 1

p(1) = 5(1)² - 3(1) + 7 = 5(1) - 3(1) + 7 = 5 - 3 + 7 = 9

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Factor the polynomial 8k^2 +80k +200
blondinia [14]
<h3>Solution:</h3>

8 {k}^{2}  + 80k + 200 \\  = 8( {k}^{2}  + 10k + 25) \\  = 8  [{k}^{2}  + 2(k)(5) +  ({5})^{2} ] \\  = 8( k + 5) ^{2}

<h3>Answer:</h3>

8( k + 5) ^{2}

<h3>Hope it helps..</h3>

ray4918 here to help

6 0
2 years ago
Question below answer correctly please
ratelena [41]

Answer:

C: x≥12

D: x<-15

E: x<7.5 or 15/2

F: x<-8

G: x≥-2.7 or -8/3

H: x≥-6

Step-by-step explanation:

I trust you know how to graph it

3 0
2 years ago
The circumference of a circle is 9.37cm.
klasskru [66]

Answer:

9.37 divide by two = 4.685

4.685 in 2DP = 4.68

Step-by-step explanation:

i hoped this helps.

4 0
2 years ago
Read 2 more answers
Level 3<br> Solve: |x + 2|– 5 = -1
leonid [27]

Answer:

x=−6

x=2

Step-by-step explanation:

Combine like terms and use the properties of equality to get the variable on one side of the equal sign and the numbers on the other side. Remember to follow the order of operations.

∣x+2∣−5=−1

Add 5 to both sides of the equation.

∣x+2∣=4

Use the definition of absolute value.

x+2=4

x+2=−4

Subtract 2 from both sides of the equation.

x=2

x=−6

6 0
3 years ago
a) The quadratic 3x^2-12x-11 can be written in the form 3(x+a)^2+b. Find the values of a and b. b) Given that the solutions of t
LenKa [72]

Answer:

Step-by-step explanation:

a) 3x^2-12x-11=3*x^2-3*2*2*x+3*4-23=3*(x^2-2*2x+2^2)-23=3*(x-2)^2-23

so  a= -2 ,b= -23

b) x1=[12+V(12^2-4*3* -11)]/6=12/6+V(144+132)/6=2+2/6V69=2+1/3V69=

2+V69/9=2+V23/3

c=2, d= 23/3

5 0
2 years ago
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