Answer:
A) True
Explanation:
Objects are known as reference types, meaning that they are always accessed by references, not copied. When a method is called, passing an object to it, Java passes a reference of that object to the method and when that reference is modified, the changes can be seen in the object itself. Therefore a mutable object can be mutated anywhere- either from where it is created or by a method it is passed to. Hence the need to always use privacy modifier keywords such as public, private or protected, to determine the exposure of class properties and methods.
Answer:
Please elaborate more your question so I can answer your question accurately.
Explanation:
Answer:
Passing by memory address
Explanation:
When you pass a memory reference like &a the data stored at this location can be directly accessed by the function through a dereference like *a = 2;
Answer:
The correct answer is "0.73 A".
Explanation:
Given that:
Power,
P = 8.3 W
Voltage,
ΔV = 11.4 V
The current will be:
⇒ ![I = \frac{P}{\Delta V}](https://tex.z-dn.net/?f=I%20%3D%20%5Cfrac%7BP%7D%7B%5CDelta%20V%7D)
On substituting the values, we get
⇒ ![=\frac{8.3}{11.4}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B8.3%7D%7B11.4%7D)
⇒ ![=0.73 \ A](https://tex.z-dn.net/?f=%3D0.73%20%5C%20A)