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DerKrebs [107]
3 years ago
15

When an object reference is passed as a parameter to a method, modifying the members of that object from inside the method will

result in a change to that object as seen from the client.
a. True
b. False
Computers and Technology
1 answer:
bogdanovich [222]3 years ago
7 0

Answer:

A) True

Explanation:

Objects are known as reference types, meaning that they are always accessed by references, not copied. When a method is called, passing an object to it, Java passes a reference of that object to the method and when that reference is modified, the changes can be seen in the object itself. Therefore a mutable object can be mutated anywhere- either from where it is created or by a method it is passed to. Hence the need to always use privacy modifier keywords such as public, private or protected, to determine the exposure of class properties and methods.

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3 years ago
The trigonometry book says: sin^2(t) + cos^2(t) = 1 Write a Python program that verifies the formula with the help of the Python
MAXImum [283]

Answer:

If you open your python-3 console and execute the following .py code you will have the following output. (Inputing 20 e.g)

Write the angles in degrees: 20

radian angles is:  0.3490658503988659

cosene( 0.3490658503988659 ) =  0.9396926207859084

sine( 0.3490658503988659 ) =  0.3420201433256687

sin^2( 0.3490658503988659 ) + cos^2( 0.3490658503988659 ) =  1.0

Explanation:

Code

import math

for i in range(1,4):

   angle = int(input('Write the angles in degrees: '))

   #mat library better works with radians

   angle_radians = (angle*math.pi)/180

   #print output

   print('radian angles is: ',angle_radians)

   print('cosene(',angle_radians,') = ',math.cos(angle_radians))

   print('sine(',angle_radians,') = ',math.sin(angle_radians))

   res = (math.sin(angle_radians))**2 + (math.cos(angle_radians))**2

   print('sin^2(',angle_radians,') + cos^2(',angle_radians,') = ',res)

6 0
3 years ago
Write a MIPS program to continuously generate the following series of integers: 1, 2, 3, 6, 9, 18, 27, 54, 81, and so on. Use st
Pachacha [2.7K]

Answer:

Explanation:

Here is a working solution in MIPS

.data

space: .asciiz ", "

.text

li $t1, 1       #Start at 1

li $t2, 1       #Store last value

li $t4, 1000    #terminate at 1000

li $t7, 2       #For division (divide by 2)

loop:

li $v0, 1

add $a0, $t1, $zero #print $t1

syscall

div $t1, $t7      #divide $t1 by 2

mfhi $t5          #get the remainder

move $t6, $t1     #hang on to what $t1 was originally

beqz $t5, even    #if the remainder is 0, it's even

add $t1,$t1,$t1    #it's odd, so add to itself

move $t2, $t6      #store what $t1 was originally to last value

bgt $t1, $t4, done #if the number is over 1000, we're done

li $v0, 4           #Print a comma and space

la $a0, space

syscall

j loop

even:

add $t1,$t1,$t2    #set $t1 = $t1 + Last value ($t2)

move $t2, $t6      #store what $t1 was originally to last value

bgt $t1, $t4, done #if the number is over 1000, we're done

li $v0, 4           #Print a comma and space

la $a0, space

syscall

j loop

done:

3 0
4 years ago
in a small town, there are two providers of broadband internet access: a cable company and the phone company. the internet acces
xz_007 [3.2K]

No, the markets is not competitive because there are not many sellers, and as such, the two providers will be able to dominate the market.

<h3>What is competitiveness in the market?</h3>

A competitive market is known to be a kind of a structure where there is nothing like a single consumer or producer that has the power to make changes to the market.

Note that the response to supply and demand tend to change with the supply curve.

Therefore, my response is No, the markets is not competitive because there are not many sellers, and as such, the two providers will be able to dominate the market.

Learn more about markets competitiveness from

brainly.com/question/25717627
#SPJ1

Are these markets competitive?

1. In a small town, there are two providers of broadband Internet access: a cable company and the phone company. The Internet access offered by both providers is of the same speed.

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