I don't think so because the old computers may have not been to date as what we have now but check it out and see.
Answer:
if(revenue.cents - expenses.cents < 0){
profit.dollars = revenue.dollars - expenses.dollars - 1;
profit.cents = 1 - revenue.cents - expenses.cents;
}
else{
profit.dollars = revenue.dollars - expenses.dollars;
profit.cents = revenue.cents - expenses.cents;
}
Explanation:
We know that profit is given as: revenue - expenses from the question.
From the given expression above;
if(revenue.cents - expenses.cents < 0)
then profit.dollar will be revenue.dollars - expenses.dollars - 1; the 1 is to be carry over to the cent part. And the profit.cent will be 1 - revenue.cents - expenses.cents;
else the profit.dollars and the profit.cent is computed directly without needing to carry over:
profit.dollars = revenue.dollars - expenses.dollars;
profit.cents = revenue.cents - expenses.cents;
My opinion is the answers A and D. I would choose A if you can only choose one, though.
Answer:
The last character in the string processed is "t".
Explanation:
The index start from 0 and the len(fruit) is 5.
When index is 0 which is less than 5; "f" is printed
When index is 1 which is less than 5; "r" is printed
When index is 2 which is less than 5; "u" is printed
When index is 3 which is less than 5; "i" is printed
When index is 4 which is less than 5; "t" is printed
When index is 5, the condition is false; so the loop content is not executed.
Therefore, the last character traversed in the string "fruit" is "t".
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