Question

What is the sum? StartFraction 3 Over x squared minus 9 EndFraction + StartFraction 5 Over x + 3 EndFraction

Answer 1

Answer:

The answer is:

$\frac{5 x - 12}{(x + 3)(x - 3)}$

Step-by-step explanation:

$\frac{3}{x ^{2} - 9} + \frac{5}{x + 3}$

First, we have to make the denorminator same by multiplying:

$\frac{3}{(x + 3)(x - 3)} + \frac{5}{x + 3}$

$\frac{3}{(x + 3)(x - 3)} + \frac{5(x - 3)}{(x + 3)(x - 3)}$

Then, we can add up everything together:

$\frac{3 + 5x - 15}{(x + 3(x - 3)}$

$\frac{5x - 12}{(x + 3)(x - 3)}$

(Sorry if being messy)

Answer 2

Answer:

Its D on egedenuity

Step-by-step explanation: