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stich3 [128]
2 years ago
8

What is the solution for xsquared= 64

Mathematics
1 answer:
nordsb [41]2 years ago
8 0
Square root both sides and you get:
X=8
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Find the area of each figure. Use 3.14 for pie.
Murrr4er [49]

Answer:

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Step-by-step explanation:

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3 years ago
Compute 1 + 2 + 3 +....+ 1,997 + 1,998 + 1,999
sp2606 [1]

Answer:

1 999 000

Step-by-step explanation:

Formula:

1+2+3+.\ .\ .+n=\frac{n\times \left( n+1\right)  }{2}

………………………………………

Then

1+2+3+....+1997+1998+1999=\frac{1999\times \left( 1999+1\right)  }{2}

1+2+3+....+1997+1998+1999=\frac{1999\times \left( 2000\right)  }{2}

1+2+3+....+1997+1998+1999=\frac{3998000  }{2}

1+2+3+....+1997+1998+1999=1999000

7 0
2 years ago
Which explanation justifies how the area of a sector of a circle is derived?
11Alexandr11 [23.1K]
The answer is option B

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3 0
3 years ago
Read 2 more answers
Which points on the curve of x^2 - xy - y^2 = 5 have vertical tangent lines?
algol [13]

We need to differentiate this with respect to x to see if we can find an expression for the derivative of y at various points.  That will be the slope of the tangent to the curve.  Then we want to see where that derivative might be infinite -- i.e., where the tangent is vertical.

 

It's not written as a function, but it can still be differentiated using the chain rule:

 

x2 + xy + y2 = 3

(2x) + (x dy/dx + y dx/dx) + (2y dy/dx) = 0

 

(I used parentheses to show the differentiation of each term in the original equation.)

 

2x + x dy/dx + y + 2y dy/dx = 0

2x + y = -x dy/dx - 2y dy/dx

2x + y = dy/dx (-x -2y)

-(2x + y)/(x + 2y) = dy/dx

 

We have the derivative of y, but it's defined partly in terms of y itself.  That's OK.  Let's go on...

 

So where would the slope be infinite?  That would happen when x + 2y = 0, or y = -x/2

 

Let's plug that in for y in the original equation to find points where that's the case.

 

x2 + xy + y2 = 3

x2 + x(-x/2) + (-x/2)2 = 3

x2 - x2/2 + x2/4 = 3

3x2 / 4 = 3

x2 = 4

x = ±2

 

So we have two x values where the tangent might be vertical.  Let's plug them into the equation and see what the y values are.  First x = 2...

 

x2 + xy + y2 = 3

4 + 2y + y2 = 3

y2 + 2y + 1 = 0

(y + 1)2 = 0

y = -1

 

So at the point (2, -1) the tangent is vertical.

 

Now try x = -2...

 

x2 + xy + y2 = 3

4 - 2y + y2 = 3

y2 - 2y + 1 =0

(y - 1)2 = 0

y = 1

 

So at the point (-2, 1) the tangent is vertical.

8 0
2 years ago
6) Triangle RST has vertices R(2,3), S(5. -1), and T(3, -4). The triangle is rotated 90° counterclockwise about the origin. Whic
Contact [7]

Answer:

  • T'(4, 3)

Step-by-step explanation:

<u>The rule of 90° counterclockwise rotation about the origin:</u>

  • (x, y) → (-y, x)

<u>Apply the rule to the point T:</u>

  • T(3, -4) → T'(4, 3)
3 0
3 years ago
Read 2 more answers
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