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3 years ago

11

Write one way of representing the equation of the given line in point-slope form. Then rewrite the equation in slope-intercept f

orm.

1 answer:

KonstantinChe [14]3 years ago

4 0

I don’t know the answer

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Solve for n 50 points <br><br> a=p(1+r/n)^rn

Andreyy89

Answer:

$n = \frac{r}{\sqrt[nt]{\frac{a}{p}} -1 }$

Step-by-step explanation:

$a=p(1+\frac{r}{n} )^{nt}$

$\frac{a}{p} =(1+\frac{r}{n} )^{nt}$

$\sqrt[nt]{\frac{a}{p}} =(1+\frac{r}{n} )$

$\sqrt[nt]{\frac{a}{p}} -1 =(\frac{r}{n} )$

$n = \frac{r}{\sqrt[nt]{\frac{a}{p}} -1 }$

[ Do not confuse, as there are 2 n's, one in subject and another as power. We can never make the power or in a root, the subject. In order to solve for n, we have to make the character "n", the subject. ]

8 0

2 years ago

What are the restrictions for a? 2a^2+a-15/5a^2+16a+3

koban [17]

ANSWER

The restrictions are

$a\ne -3,a\ne -\frac{1}{5}$

EXPLANATION

We were given the rational function,

$\frac{2a^2+a-15}{5a^2+16a+3}$

The function is defined for all values of a, except

$5a^2+16a+3=0$

This has become a quadratic trinomial, so we need to split the middle term.

We do that by multiplying the coefficient of $x^2$ which is 5 by the constant term which is 3. This gives us 15.

The factors of 15 that adds up to 16 are 1 and 15.

We use these factors to split the middle term.

$5a^2+15a+a+3=0$

We now factor to get,

$5a(a+3)+1(a+3)=0$

We factor further to get,

$(a+3)(5a+1)=0$

This implies that,

$(a+3)=0,(5a+1)=0$

This gives

$a=-3,a=-\frac{1}{5}$

These are the restrictions.

8 0

4 years ago

If 15/3 greater than 7, then 15/7 is less than 3 true or false

Ludmilka [50]

Answer:

True

Step-by-step explanation:

15/7 is about 2.14 which is less than 3

3 0

3 years ago

A sample of 25 undergraduates reported the following dollar amounts of entertainment expenses last year:

marin [14]

Answer:

$Range = 85$

$\sigma = 28.71$

$Interval = [666.78, 781.62]$

Step-by-step explanation:

Given

The data for 25 undergraduates

Solving (a): Range and Standard deviation

The range is:

$Range = Highest - Least$

From the dataset:

$Highest = 772$

$Least = 687$

So:

$Range = Highest - Least$

$Range = 772-687$

$Range = 85$

The standard deviation is:

$\sigma = \sqrt{\frac{\sum(x - \bar x)^2}{n}}$

First, calculate the mean

$\bar x = \frac{769 +691 +............+715}{25}$

$\bar x = \frac{18105}{25}$

$\bar x = 724.2$

So, the standard deviation is:

$\sigma = \sqrt{\frac{(769-724.2)^2 +(691-724.2)^2 +(699-724.2)^2 +(730-724.2)^2 +............+(715-724.2)^2}{25}}$

$\sigma = \sqrt{\frac{20604}{25}}$

$\sigma = \sqrt{824.16}$

$\sigma = 28.71$

Solving (b): The interval of the 95% of the observation.

Using the emperical rule, we have:

$Interval = [\bar x - 2*\sigma, \bar x+ 2*\sigma]$

$Interval = [724.2 - 2*28.71, 724.2 + 2*28.71]$

$Interval = [666.78, 781.62]$

4 0

3 years ago

What is the improper fraction for 5 1/3

Yakvenalex [24]

Hey there Shawn!

$\left[\begin{array}{ccc}\boxed{\boxed{ 5\frac{1}{3}= \frac{16}{3} }} \ as \ an \ improper \ fraction\end{array}\right]$

Hope this helps you budd!

5 0

3 years ago