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PSYCHO15rus [73]
3 years ago
8

Will get lots of points!! Thank you!! Trigonometry

Mathematics
1 answer:
katrin2010 [14]3 years ago
7 0

Answer:

Angle B =  75 degrees

AC =  35.7

BC =  9.6

Step-by-step explanation:

Angle A = 15 degrees (given)

Angle C = 90 degrees (given)

c = 37 (given)

Angle B = 90-15 = 75 degrees

AC = AB cos(A) = 37 cos(15) = 35.7

BC = AB sin(A) = 37 sin(15) = 9.6

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the expression 1350(1.05)^t models the average wages, in dollar, in the us as a function of the number of years since 1930. what
barxatty [35]

Answer:

The average wage in the us increase by about five percent

Step-by-step explanation:

3 0
3 years ago
X - 5 &lt; - 3 <br> Or<br> X + 8 &gt; 2
Alex Ar [27]

Step-by-step explanation:

x-5 < -3

or, x < -3 +5

or, x < 2

Now,

x +8 >2

or, x >2 - 8

or, x >-6

7 0
2 years ago
How much greater will Jennifer’s January finance charge be if the finance charge is calculated using the previous balance method
victus00 [196]
The answer to this is C
6 0
3 years ago
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The fountain is made up of two semicircles and a quarter circle. Find the perimeter and the area of the fountain. Round the peri
Andrej [43]
FOUND THE COMPLETE QUESTION IN ANOTHER SOURCE.ATTACHED IMAGE.
 For this case what we have is the following:
 For the two semicircles we can model it as a complete circle.
 We have to then:
 
 Perimeter: 
 P = 2 * pi * r
 or
 P = pi * d
 Where,
 r = radius
 d = diameter
 Therefore the perimeter is:
 P = 10 * pi
 For the largest circle we have:
 radius = 10
 Perimeter:
 P '= 2pi10
 P '= 20pi
 1/4 since 1/4 circle:
 P '' = 20pi / 4 = 5pi
 Then, the total perimeter of the source is:
 Pt = P + P '' = 10pi + 5pi = 15pi
 Pt = 15 * (3.141592)
 Pt = 47.1239
 round
 Pt = 47.1 ft

 Area:
 The total area will be:
 A = A (two semicircles) + A (quarter big circle)
 A = (pi / 4) * (d ^ 2) + (1/4) * pi * r ^ 2
 A = (pi / 4) * ((10) ^ 2) + (1/4) * pi * (5) ^ 2
 A = 98.17477042 feet ^ 2
 Round:
 A = 98.2 feet ^ 2

 Answer: 
 Perimeter of the source: 
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 Area of the source: 
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5 0
3 years ago
Can someone help me find the equivalent expressions to the picture below? I’m having trouble
miss Akunina [59]

Answer:

Options (1), (2), (3) and (7)

Step-by-step explanation:

Given expression is \frac{\sqrt[3]{8^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}.

Now we will solve this expression with the help of law of exponents.

\frac{\sqrt[3]{8^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}=\frac{\sqrt[3]{(2^3)^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}

           =\frac{\sqrt[3]{2\times 3} }{3\times2^{\frac{1}{9}}}

           =\frac{2^{\frac{1}{3}}\times 3^{\frac{1}{3}}}{3\times 2^{\frac{1}{9}}}

           =2^{\frac{1}{3}}\times 3^{\frac{1}{3}}\times 2^{-\frac{1}{9}}\times 3^{-1}

           =2^{\frac{1}{3}-\frac{1}{9}}\times 3^{\frac{1}{3}-1}

           =2^{\frac{3-1}{9}}\times 3^{\frac{1-3}{3}}

           =2^{\frac{2}{9}}\times 3^{-\frac{2}{3} } [Option 2]

2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(\sqrt[9]{2})^2\times (\sqrt[3]{\frac{1}{3} } )^2 [Option 1]

2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(\sqrt[9]{2})^2\times (\sqrt[3]{\frac{1}{3} } )^2

                =(2^2)^{\frac{1}{9}}\times (3^2)^{-\frac{1}{3} }

                =\sqrt[9]{4}\times \sqrt[3]{\frac{1}{9} } [Option 3]

2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(2^2)^{\frac{1}{9}}\times (3^{-2})^{\frac{1}{3} }

               =\sqrt[9]{2^2}\times \sqrt[3]{3^{-2}} [Option 7]

Therefore, Options (1), (2), (3) and (7) are the correct options.

6 0
2 years ago
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