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hram777 [196]
3 years ago
13

The endpoints of EF¯¯¯¯¯ are located at E (−3, 2) and F (3, 8). Point D divides EF¯¯¯¯¯ such that ED : DF is equal to 1 : 3. For

each box, select the values in the dropdown that make the statement true. The x-coordinate of point D is and the y-coordinate of point D is
Mathematics
1 answer:
arlik [135]3 years ago
3 0

Answer:

D(x,y) = (-1.5,3.5)

Step-by-step explanation:

Given

E = (-3,2)

F = (3,8)

ED: DF = 1 : 3

Required

Determine the coordinates of D

This is calculated as thus:

D(x,y) = (\frac{mx_2 + nx_1}{m+n},\frac{my_2 + ny_1}{m+n})

Where:

(x_1,y_1) = (-3,2)

(x_2,y_2) = (3,8)

m:n = 1:3

D(x,y) = (\frac{mx_2 + nx_1}{m+n},\frac{my_2 + ny_1}{m+n})

D(x,y) = (\frac{1 * 3 + 3 *-3}{1+3},\frac{1 * 8 + 3 * 2}{1+3})

D(x,y) = (\frac{-6}{4},\frac{14}{4})

D(x,y) = (-1.5,3.5)

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Find f(-2) for the following function. <br><br>f(x)=3.6x-2​
butalik [34]

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Step-by-step explanation:

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1-sin^2x/sinx-cscx <br><br>How do I solve this problem? I keep getting the wrong answer.
Annette [7]

Answer:

-sinx

Step-by-step explanation:

a trig identity that is crucial to solving this problem is: sin^2 + cos^2 = 1

with knowing that, you can manipulate that and turn it into 1 - sin^2x = cos^x

so 1-sin^2x/sinx - cscx becomes cos^2x/sinx - cscx

it is also important to know that cscx is the same thing as 1/sinx

knowing this information, cscx can be replaced with 1/sinx

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now sinx and 1/sinx do not have the same denominator, so we need to multiply top and bottom of sinx by sinx; it becomes....

cos^2x

---------------------

(sin^2x - 1)/sinx

notice how in the denominator it has sin^2x-1 which is equal to -cos^2x

so now it becomes:

cos^2x

--------------

-cos^2x/sinx

because we have a fraction over a fraction, we need to flip it

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---------- * ----------------

1                  -  cos^2x

because the cos^2x can cancel out, it becomes 1

now the answer is -sinx

3 0
3 years ago
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