Hi there!
The inequality for this situation is
12x + 4 <= 23
Where <em>x </em>is the number.
Hope this helps!
Answer:
4
Step-by-step explanation:
Given:
A, B, C, D have distinct positive values for mod 6
A (mod 6) = 1
B (mod 6) = 2
C (mod 6) = 4
D (mod 6) = 5
Each mod 6 value cannot be a zero since the product ABCD is not a multiple of 6.
Furthermore, in order that ABCD mod 6 > 0, we cannot have a residue equal to 3, else the product with a residue 2 or 4 will make the product a multiple of 6.
Thus the only positive residues can only be 1,2,4,5
A*B*C*D (mod 6) > 0 = 1*2*4*5 (mod 6) = 4
Honestly not exactly sure what the answer to this here question is
Answer:
93
Step-by-step explanation:
5533 divided by 81 is 93
