Question

Which ordered pair is part of the solution set of the inequality 12 + y ≤ –3x? Question 11 options: a) (3, –16) b) (4, –1) c) (–16, 3) d) (1, 4)

Answer 1

Answer:

c) (-16,3)

Step-by-step explanation:

Given: inequality $12+\text{y}\leq -3\text{x}$

To Find: Which ordered pair is part of the solution set of the inequality

Solution:

Simplifying inequality,

$12+\text{y}\leq -3\text{x}$

$12}\leq -3\text{x}-\text{y$

now,

putting ordered pairs from options

a) $(3,-16)$

$-3\times3-(-16)$$16-9=7$

as $7$, it does not satisfy inequality

b)  $(4,-1)$

$-3\times4-(-1)$$1-12=-11$

as $-11$, it does not satisfy inequality

c)  $(-16,3)$

$-3\times(-16)-(3)$$48-3=45$

as $45>12$, it satisfy inequality

d)  $(1,4)$

$-3\times1-(4)$$-3-4=-7$

as $-7$, it does not satisfy inequality

So, from above only option c is part of the solution set of inequality.

Answer 2

Answer:

C (-16, 3)

Step-by-step explanation:

$12 + 3 \leqslant - 3 \times - 16 \\ 15 \leqslant 48$

replace x and y