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3 years ago

1+1=2 but 2-1=3 so how does 1+1=2

Mathematics

2 answers:

Kobotan [32]3 years ago

6 0

Answer:

haber ...

Step-by-step explanation

:que sepas que 2menos 1 no es 3, 1e

bagirrra123 [75]3 years ago

5 0

Answer:

cause one is one so add another is 2 and 2-1 is not 3

Step-by-step explanation:

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(1/4)^3z-1 =16^z+2*64^z-2 Z=___ Please help

wariber [46]

Answer:

Z = 0.198877274

Step-by-step explanation:

$(\frac{1}{4})^{3z-1} = 16^z + 2*16^{z-2}\\4^{1-3z} = 4^{2z} + 4^{\frac{1}{2}}*4^{2z-4}\\4^{1-3z} = 4^{2z} + 4^{2z-4+\frac{1}{2}}\\4^{1-3z} = 4^{2z} + 4^{2z-\frac{7}{2}}\\4^{1-3z} = 4^{2z} *(1+ 4^{-\frac{7}{2}})\\4^{1-3z} = 4^{2z} *(1+ 2^{-7})\\4^{1-3z} = 4^{2z} *(1+ \frac{1}{128} )\\4^{1-3z} = 4^{2z} *(\frac{129}{128} )\\Taking\;\; Logarithm\;\; with\;\; base\;\; 4\\Log_4(4^{1-3z}) = Log_4(4^{2z}) + Log_4(\frac{129}{128})\\1-3z = 2z + 0.005613627712 \\5z = 0.994386372\\z = 0.198877274$

Hence, the value of Z = 0.198877274

8 0

3 years ago

Read 2 more answers

Which expression is equivalent to 5+5t+3t+?

FrozenT [24]

Answer:

10t+3

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

An urn contains 5 white and 10 black balls. A fair die is rolled and that number of balls is randomly chosen from the urn. What

galina1969 [7]

Answer:

Part A:

The probability that all of the balls selected are white:

$P(A)=\frac{1}{6}(\frac{1}{3}+\frac{2}{21}+\frac{2}{91}+\frac{1}{273}+\frac{1}{3003}+0)\\ P(A)=\frac{5}{66}=0.075757576$

Part B:

The conditional probability that the die landed on 3 if all the balls selected are white:

$P(D_3|A)=\frac{\frac{2}{91}*\frac{1}{6}}{\frac{5}{66} } \\P(D_3|A)=\frac{22}{455}=0.0483516$

Step-by-step explanation:

A is the event all balls are white.

D_i is the dice outcome.

Sine the die is fair:

$P(D_i)=\frac{1}{6}$ for i∈{1,2,3,4,5,6}

In case of 10 black and 5 white balls:

$P(A|D_1)=\frac{5_{C}_1}{15_{C}_1} =\frac{5}{15}=\frac{1}{3}$

$P(A|D_2)=\frac{5_{C}_2}{15_{C}_2} =\frac{10}{105}=\frac{2}{21}$

$P(A|D_3)=\frac{5_{C}_3}{15_{C}_3} =\frac{10}{455}=\frac{2}{91}$

$P(A|D_4)=\frac{5_{C}_4}{15_{C}_4} =\frac{5}{1365}=\frac{1}{273}$

$P(A|D_5)=\frac{5_{C}_5}{15_{C}_5} =\frac{1}{3003}=\frac{1}{3003}$

$P(A|D_6)=\frac{5_{C}_6}{15_{C}_6} =0$

Part A:

The probability that all of the balls selected are white:

$P(A)=\sum^6_{i=1} P(A|D_i)P(D_i)$

$P(A)=\frac{1}{6}(\frac{1}{3}+\frac{2}{21}+\frac{2}{91}+\frac{1}{273}+\frac{1}{3003}+0)\\ P(A)=\frac{5}{66}=0.075757576$

Part B:

The conditional probability that the die landed on 3 if all the balls selected are white:

We have to find $P(D_3|A)$

The data required is calculated above:

$P(D_3|A)=\frac{P(A|D_3)P(D_3)}{P(A)}\\ P(D_3|A)=\frac{\frac{2}{91}*\frac{1}{6}}{\frac{5}{66} } \\P(D_3|A)=\frac{22}{455}=0.0483516$

7 0

3 years ago

(5.27) An owner of a home in the Midwest installed solar panels to reduce heating costs. After installing the solar panels, he m

harkovskaia [24]

The regression line equation is $y=85+16x$ , the value of the slope is shown as constant 16 and it's a positive constant, hence the correlation between the amount of gas used and degree of the days is a POSITIVE correlation.

5 0

3 years ago

PLEASE SHOW FULL SOLUTIONS !!!!! WILL MARK BRAINLIEST FOR THE BEST ANSWER. THANK YOU AND GOD BLESS

yanalaym [24]

Answer:

System is given below

Step-by-step explanation:

Let (applicable to all three lines below)
Hard candy = x kg with price $1.60/kg
Gummy worms = y kg with price $2.20/kg
Total weight = 50 kg with mixed price $1.75/kg

Required equations:

x + y = 50 total weight
1.60x + 2.20y = 50*1.75 total price

=========================================

Note. It says don't solve but the solution below for those who is interested to know the answer.

Simplify the second equation and solve by substitution x = 50 - y:

1.6(50 - y) + 2.2y = 87.5
80 - 1.6y +2.2y = 87.5
0.6y = 7.5
y = 7.5/0.6
y = 12.5

Find the value of x:

x = 50 - 12.5 = 37.5

Hard candy = 37.5 kg and gummy worms = 12.5 kg

7 0

2 years ago