F(x) = 3x + 7.....g(x) = 4x - 2
A. (f + g)(x)
3x + 7 + 4x - 2
7x + 5 <====
B. (f * g)(x)
(3x + 7)(4x - 2) =
3x(4x - 2) + 7(4x - 2) =
12x^2 - 6x + 28x - 14
12x^2 + 22x - 14 <===
C. f[g(x)]
3(4x - 2) + 7 =
12x - 6 + 7 =
12x + 1 <===
Answer:
6 days
Step-by-step explanation:
pay 60 = -60
Let d = the number of days
30d - 60 = sister
20d = me
Equation:
30d - 60 = 20d Move 30 to the other side
-30d -30d
-60 = 20d - 30d Combine liked terms
-60 = -10d
-10 -10 Divide
d = 6
Answer:
The larger number is -6, the smaller number is -15
Step-by-step explanation:
We have two numbers, a and b.
We know that one number is larger than another by 9.
Then we can write:
a = b + 9
then a is larger than b by 9 units.
If the greater number is increased by 10 (a + 10) and the lesser number is tripled (3*b), the sum of the two would be -41:
(a + 10) + 3*b = -41
So we got two equations:
a = b + 9
(a + 10) + 3*b = -41
This is a system of equations.
One way to solve this is first isolate one variable in one of the two equations:
But we can see that the variable "a" is already isolated in the first equation, so we have:
a = b + 9
now we can replace that in the other equation:
(a + 10) + 3*b = -41
(b + 9) + 10 + 3*b = -41
now we can solve this for b.
9 + b + 10 + 3b = -41
(9 + 10) + (3b + b) = -41
19 + 4b = -41
4b = -41 -19 = -60
b = -60/4 = -15
b = -15
then:
a = b + 9
a = -15 + 9 = -6
a = -6