Speed (S) = Distance (D) / time (t)
First stretch
45 = D / 2
D = 45*2
D = 90 mp
How is the same distance:
Second stretch
S = 90 / t
Average speed (AS):
AS = (S1+S2) / 2
60 = [45+(90/t)] / 2
120 = 45+90/t
120-45 = 90/t
75 = 90/t
t = 90/75
t = 1,2 h
________________________
And now:
S = 90 / t
S = 90 / 1,2
S = 75 mph
Four is greater than y, and -1 is less than y

Answer:
0 is an inflection point
1/4 is a local maximum.
Step-by-step explanation:
To begin with you find the first derivative of the function and get that

to find the critical points you equal the first derivative to 0 and get that

To find if they are maximums or local minimums you use the second derivative.

since
is neither an inflection point, and since
then 1/4 is a maximum.
All three are similar
In ∆SUT and ∆VWX
- Two sides are similar and one angle is similar
So by SSA they are similar
In ∆PRQ and rest two
All angles are.
So
They are similar by AAA congruence
Answer:
A is
Step-by-step explanation: