Answer:c. Y=(x-3)^2-2
Step-by-step explanation: y=(x-3)^2-2
Y=x^2-6x+7
Let's find the least possibilities:
First number: 6
Second number: 8
Third number: 10
6 + 8 + 10 = 24
Now we can see that we are still missing 31 - 24 = 7.
7 can be gained by adding 3 and 4, so:
First number: 6 + 3 = 9
Second number: 8 + 4 = 12
Third number: 10
9 + 12 + 10 = 31
When the first number increases by one the second number is added by 4's. So from the first part to the second it added 4 then from the 2nd to the 3rd it skips adding 8 to then just add 12. Then from the 3rd to the 4th it skips adding 16 and adds 20. So the next set of numbers would be (4,64) because it skips adding the 24 and adds the 28.
Hope this helps and is not to confusing :)
Answer:
with what?
Step-by-step explanation:
