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Dimas [21]
4 years ago
13

Find the direct variation equation of the graph through the points (0, 0) and (1, -2). Write in y=kx form.

Mathematics
2 answers:
Romashka [77]4 years ago
5 0
1. ( y - 0)/( -2 - 0) = (x - 0)/(1 - 0);
Then, y/(-2) = x/1;
finalyy, y = -2x;
The correct answer is B.

2. In the same way, we obtain y =4x; the correct answer is A.
weeeeeb [17]4 years ago
5 0
The direct variation between x and y may be expressed as y = kx where k is the constant of variation. Substitute the values of the abscissa to the x and ordinates to the y's to get the k's

1. 0 = k(0)     ; -2 = k(1)    ; k = -2.  
  Therefore, the direct variation is y = -2x. The answer is letter B.

2. 0 = k(0)     ; 1 = k(4)     ; k = 1/4
  Therefore, the direct variation is y = (1/4) x. The answer is letter C. 
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Mademuasel [1]

Answer:

f(x) = x/4

Step-by-step explanation:

To find the inverse of a function replace the positions of x and y. Then isolate y.

y = 4x

x = 4y

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5 0
3 years ago
Angle 1 and Angle 2 are supplementary. Angle 1 is 20 degree less than nine times the size of angle 2.
nadya68 [22]

Answer:

∠1=160° and ∠2=20°

Step-by-step explanation:

Let ∠1 = x

∠2 = y

as these two angles are supplementary their sum is 180

that x+y=180   ----(A)

Also given that ∠1 is 20 degree less than nine times the size of ∠2.

Hence

x=9y-20

putting value of x in A and solving for y

9y-20+y=180

10y=180+20

10y=200

y=10

Putting this y in A

x+10=180

x=160

5 0
3 years ago
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boyakko [2]
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3 years ago
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liraira [26]
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