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Marina86 [1]
3 years ago
14

a 50-meter path surrounds a rectangular garden. The width of the garden is five meters less than its length. Find the length and

width.
Mathematics
1 answer:
rewona [7]3 years ago
4 0
Suppose length is X -----> [1]
so the width is X - 5 -----> [2]

perimeter of rectangle = 2 ( length + width )
50 = 2 ( X + X - 5 )
50 = 2 ( 2X - 5 )
50 = 4X - 10
50 + 10 = 4X
60 = 4X
60/4 = X
15 = X

subsitute in [1] and [2]
length = 15 meters
width = 15 - 5 = 10 meters
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The value of y when x is equal to 10 is 30. This is because for every value of x the value of y is 3. This can be known if you divide 24 by 8 you get 3. So if x=10 then y would equal 30. 
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Y-3x=-2<br> 3x=y+6<br> Solve system..
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Answer:

This equation system has no answer

Step-by-step explanation:

y - 3x =  - 2..................(1) \\ 3x -y = 2.....................(2) \\ 3x = y + 6.....................(3) \\ 3x - y = 6.....................(4) \\ (4) - (2) \\ 0 = 4

3 0
3 years ago
Can someone help me with this???
Veseljchak [2.6K]
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8 0
3 years ago
(08.07 HC)
andreev551 [17]

Answer:

\textsf{A)} \quad x=-2, \:\:x=\dfrac{5}{2}

\textsf{B)} \quad \left(\dfrac{1}{4},-\dfrac{81}{8}\right)=(0.25,-10.125)

C)  See attachment.

Step-by-step explanation:

Given function:

f(x)=2x^2-x-10

<h3><u>Part A</u></h3>

To factor a <u>quadratic</u> in the form  ax^2+bx+c<em> , </em>find two numbers that multiply to ac and sum to b :

\implies ac=2 \cdot -10=-20

\implies b=-1

Therefore, the two numbers are -5 and 4.

Rewrite b as the sum of these two numbers:

\implies f(x)=2x^2-5x+4x-10

Factor the first two terms and the last two terms separately:

\implies f(x)=x(2x-5)+2(2x-5)

Factor out the common term  (2x - 5):

\implies f(x)=(x+2)(2x-5)

The x-intercepts are when the curve crosses the x-axis, so when y = 0:

\implies (x+2)(2x-5)=0

Therefore:

\implies (x+2)=0 \implies x=-2

\implies (2x-5)=0 \implies x=\dfrac{5}{2}

So the x-intercepts are:

x=-2, \:\:x=\dfrac{5}{2}

<h3><u>Part B</u></h3>

The x-value of the vertex is:

\implies x=\dfrac{-b}{2a}

Therefore, the x-value of the vertex of the given function is:

\implies x=\dfrac{-(-1)}{2(2)}=\dfrac{1}{4}

To find the y-value of the vertex, substitute the found value of x into the function:

\implies f\left(\dfrac{1}{4}\right)=2\left(\dfrac{1}{4}\right)^2-\left(\dfrac{1}{4}\right)-10=-\dfrac{81}{8}

Therefore, the vertex of the function is:

\left(\dfrac{1}{4},-\dfrac{81}{8}\right)=(0.25,-10.125)

<h3><u>Part C</u></h3>

Plot the x-intercepts found in Part A.

Plot the vertex found in Part B.

As the <u>leading coefficient</u> of the function is positive, the parabola will open upwards.  This is confirmed as the vertex is a minimum point.

The axis of symmetry is the <u>x-value</u> of the <u>vertex</u>.  Draw a line at x = ¹/₄ and use this to ensure the drawing of the parabola is <u>symmetrical</u>.

Draw a upwards opening parabola that has a minimum point at the vertex and that passes through the x-intercepts (see attachment).

5 0
2 years ago
-3/4(x-3)-5= 1/8 (x-1)
earnstyle [38]
I think it’s 1384939384$3
6 0
3 years ago
Read 2 more answers
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