1. Take an arbitrary point that lies on the first line y=3x+10. Let x=0, then y=10 and point has coordinates (0,10).
2. Use formula  to find the distance from point
 to find the distance from point  to the line Ax+By+C=0.
 to the line Ax+By+C=0.
The second line has equation y=3x-20, that is 3x-y-20=0. By the previous formula the distance from the point (0,10) to the line 3x-y-20=0 is:
 .
.
3. Since lines y=3x+10 and y=3x-20 are parallel, then the distance between these lines are the same as the distance from an arbitrary point from the first line to the second line.
Answer:  .
.
 
        
             
        
        
        
Answer:
0.927
Step-by-step explanation:
add then round the last digit (it doesnt matter if it is a decimal number or not).
 
        
             
        
        
        
Use y=Mx+B plug in correct spot
        
             
        
        
        
√((25x^9y^3)/(64x^6y^11))  doing the normal division within the radical
√((25x^3)/(64y^8)  then looking at the squares within the radical...
√((5^2*x^2*x)/(8^2*y^8))  now we can move out the perfect squares...
(5x/(8y^4))√x
So it is the bottom answer...