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Ray Of Light [21]
3 years ago
8

How is the molar heat of sublimation related to the molar heats of vaporization and fusion? On what law are these relationships

based?
Chemistry
1 answer:
Dovator [93]3 years ago
3 0

Answer: Hsub=Hfus+Hvap

Explanation:

The molar heat of vaporization measured in kilojoules per mole, or kJ/mol is the energy needed to make vapor one mole of a liquid. .

The molar heat of sublimation measured in kilojoules per mole, or kJ/mol is the energy needed to sublime one mole of a solid,

the molar heat of fusion measured in kilojoules per mole, or kJ/mol is the energy needed to melt one mole of a solid.

Hess law helps to explain the relationship in physical chemistry stating that the total enthalpy change during the complete course of a reaction is the same whether the reaction is made in one step or in several steps.

In this context Hess’s law helps to see the several steps involved as the heat of sublimation energy is equal to the sum of vaporization energy and fusion energy.

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3.2 moles of H3PO4 to grams
Nimfa-mama [501]

Answer:

313, 6grams of H3PO4

Explanation:

We calculate the weight of 1 mol of H3PO4:

Weight 1 mol H3PO4= (Weight H)x3+ (Weight P)+(Weight 0)x4  =1gx3+31g+16gx4

Weight 1 mol H3PO4=98 g /mol

1 mol-----98 grams H3PO4

3,2mol----x= (3,2molx 98 grams H3PO4)/ 1mol=313,6 grams H3PO4

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amid [387]

Answer:

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Explanation:

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4 0
3 years ago
What is the answer please
xeze [42]

Answer:

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Explanation:

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6 0
4 years ago
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Alexandra [31]

Answer:

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Explanation:

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4 0
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