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4 years ago

What is the oxidation number of the element ge in the compound geo2?

1 answer:

3 0

Oxygen has an oxidation state of -2 so considering that there are 2 oxygen atoms,
2 x -2 = -4
The compound is neutrally charged so the sum of all the oxidation states must be zero. Therefore the oxidation state of Ge must be +4 in order to cancel the -4 to make zero.

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Consider the unbalanced equation for the oxidation of aluminum. _Al + _O2 mc031-1.jpg _Al2O3 Which sequence of coefficients shou

sdas [7]

The options are
<span>2, 3, 1
1, 3, 2
4, 3, 2
3, 2, 3

when balancing equation the masses should be balanced. In other </span>words the same number of atoms of the same element should be on either side of the equation

the balanced equation for the oxidation of aluminium is as follows

4Al + 3O₂ ---> 2Al₂O₃
coefficients are the numbers in front of the respective compounds.
the coefficients in the correct sequence are 4,3 and 2

answer is 4, 3, 2

3 0

4 years ago

Read 2 more answers

When 2.5 g of blue copper(ii) sulfate crystals were heated, 1.6 g of a white solid were left in tube A

Zinaida [17]

Answer:

b po answerpa brainlest

8 0

3 years ago

Name 3 different uses for nuclear technology

AlekseyPX

Agriculture, space exploration, and also for medical purposes.

Hope I helped :)

6 0

3 years ago

In physical changes, the atoms or molecules that compose the matter do not change their identity, even though the matter may cha

slavikrds [6]

Answer:

True

Explanation:

when a physical change occurs in a substance, the appearance might change but the chemical identity remains same. For example, if liquid water is heated, the water changes to gaseous form .This means the appearance of the water has changed, but the chemical identity remains same as both liquid water and steam has both oxygen and hydrogen as the component molecules or atoms.

3 0

4 years ago

Propane C3H8 is a hydrocarbon tht is commonly used as a fuel

Mariulka [41]

Answer:C3H8 +5O2-- >3CO2+4H2O, 330L of air,Hof C3H8= 2323.7 KJ/mol,dT=75.30

Explanation:

First We need to find a balanced equation to depict the combustion of the propane:

C3H8 +5O2-- >3CO2+4H2O

$25g C3H8*\frac{1mol C3H8}{44gC3H8} *\frac{5molO2}{1molC3H8}* \frac{32gO2}{1mol O2}*\frac{1L air}{0.275g}$

330L of air

25 g C3H8 are equal to 44g and 5 mol of O2 will react with a mol of C3H8, each mol of O2 weigh 32g and for each L of air contains 0.275g of O2

c) $Hof C3H8= -(-285.8\frac{KJ}{mol}*4mol +-393.5*3mol$

the enthalpy of formation of propane will be the negative of the sum of the enthalpy of formation multiplied by the mols of the H2O and CO2

Hof C3H8= 2323.7 KJ/mol

d) We know that each 44g of C3H8(1mol) transfer 2219.2 KJ then:

$25g\frac{2219.2KJ}{44g C3H8}$ = 1260.9KJ

We use the equation of heat transfered

Q=mCpdT

1260.9KJ= 4KJ *4.186KJ/Kg*°C *dT

We clear the equation

Q/mCp=dT

dT=75.30

4 0

3 years ago