the data represents the heights of fourteen basketball players, in inches. 69, 70, 72, 72, 74, 74, 74, 75, 76, 76, 76, 77, 77, 8
Daniel [21]
If you would like to know the interquartile range of the new set and the interquartile range of the original set, you can do this using the following steps:
<span>The interquartile range is the difference between the third and the first quartiles.
The original set: </span>69, 70, 72, 72, 74, 74, 74, 75, 76, 76, 76, 77, 77, 82
Lower quartile: 72
Upper quartile: 76.25
Interquartile range: upper quartile - lower quartile = 76.25 - 72 = <span>4.25
</span>
The new set: <span>70, 72, 72, 74, 74, 74, 75, 76, 76, 76, 77, 77
</span>Lower quartile: 72.5
Upper quartile: 76
Interquartile range: upper quartile - lower quartile = 76 - 72.5 = 3.5
The correct result would be: T<span>he interquartile range of the new set would be 3.5. The interquartile range of the original set would be more than the new set.</span>
Answer:
(–1, –6)
Step-by-step explanation:
Given that S(3, –5) was translated to S'(–4, 1), the transformation rule is (x-7, y+6). Then, the coordinates of square RSTU are:
R'(–8, 1) -> (-8+7, 1-6) -> R(-1, -5)
S'(–4, 1) -> (-4+7, 1-6) -> S(3, -5)
T'(–4, –3) -> (-4+7, -3-6) -> T(3, -9)
U'(–8, –3) -> (-8+7, -3-6) -> U(-1, -9)
The point (–1, –6) lies on the segment RU
Answer:
10
Step-by-step explanation:
Given:it takes them 1.5 hours to plant one acre.
So, in order to plant all 15 acres it would take
15/1.5 = 10 hours
The area of the square will be 196cm².
<h3>How to calculate the area?</h3>
It should be noted that the perimeter of a square is the addition of all its sides. Therefore, the length of the side will be:
= 56/4
= 14
Therefore, the area of the figure will be:
= 14²
= 14 × 14
= 196cm²
Learn more about area on:
brainly.com/question/25292087
#SPJ1
Step-by-step explanation:
"Solutions to the equation" just means that they are points on the line. To find out if these two points land on this line, plug each one in, like this:
1.5 = (1/4)(1) + (5/4)
1.5 = (1/4) + (5/4)
1.5 = (6/4)
1.5 = 1.5
Since the expression is true, this point is on the line.
Do the same process for the second point (remember a point is formatted (x,y)) and see if it is also a point on the line.
To find the x-intercept, simply plug in 0 for y and see what you get. It should look like (x,0).
