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aleksandr82 [10.1K]
3 years ago
15

Fine the area of a circle whose radius measures 12 cm

Mathematics
1 answer:
larisa86 [58]3 years ago
5 0
The answer should be 7234.56
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a circle has a circumstance of 20. it has an arc on length 4. what is the central angle of the arc in degrees?
erastovalidia [21]

Answer:

∠72°.

Step-by-step explanation:

If a circle has a circumference of 20 and an arc with a length of 4, we can simply set up a ratio to determine the angle of the arc in degrees:

\frac{4}{20} = \frac{x}{360}

Cross multiply:

1440 = 20x\\

Divide both sides by '20':

x = 72°.

Therefore, the measure of the central angle of the arc is ∠72°.

4 0
3 years ago
What is the solution to the equation 1/3 (x - 2) = 1/5 (x + 4) + 2?
allsm [11]
The solution is x=26
6 0
4 years ago
Read 2 more answers
HELP SUPER EASY HELP HELP GELP GELP HELP WHAT IS THE ANSEER
Zepler [3.9K]

Answer:

8.9%

Step-by-step explanation:

7 0
3 years ago
Answer ASAP, Will give brainliest
erastova [34]

Answer:

Step-by-step explanation:

1) ABCD is a trapezium. AB ║ CD

∠ADC + ∠DAB  = 180°  { Co interior angles}

110° + ∠DAB = 180

         ∠DAB = 180 -110

∠DAB = 70°

2) Sum of all angles of trapezium = 360°

∠A + ∠B + ∠DCB + ∠D = 360

70° + 50° + ∠DCB + 110° = 360

                 230 + ∠DCB = 360

                            ∠DCB = 360 - 230

∠DCB = 130°

3) For finding the height, use Pythagorean theorem

height² + base² = hypotenuse²

      height² + 6² = 10²

      height² + 36 =100

               height² = 100 - 36

              height² = 64

               height = √64

height = 8 m

4) a = AB = x m

  b = 9 m

h = height = 8 m

Area of trapezium = 120 m²

\frac{(a+b)*h}{2}\\\\  = 120

\frac{(x+9)*8}{2} =120\\\\\\(x +9)*4 = 120

x + 9 = 120/4

x + 9 = 30

    x = 30 - 9

x = 21 m

AB = 21m

                             

7 0
3 years ago
The graph 4x^2-4x-1 is shown. Use the grpah to find the estimates for the solutions of 4x^2-4x-1=0 and 4x^2 - 4x-1=2
Darina [25.2K]

Answer:

a) The estimates for the solutions of 4\cdot x^{2}-4\cdot x -1 = 0 are x_{1}\approx -0.25 and x_{2} \approx 1.25.

b) The estimates for the solutions of 4\cdot x^{2}-4\cdot x -1 = 2 are x_{1}\approx -0.5 and x_{2} \approx 1.5

Step-by-step explanation:

From image we get a graphical representation of the second-order polynomial y = 4\cdot x^{2}-4\cdot x -1, where x is related to the horizontal axis of the Cartesian plane, whereas y is related to the vertical axis of this plane. Now we proceed to estimate the solutions for each case:

a) 4\cdot x^{2}-4\cdot x -1 = 0

There are two approximate solutions according to the graph, which are marked by red circles in the image attached below:

x_{1}\approx -0.25, x_{2} \approx 1.25

b) 4\cdot x^{2}-4\cdot x -1 = 2

There are two approximate solutions according to the graph, which are marked by red circles in the image attached below:

x_{1}\approx -0.5, x_{2} \approx 1.5

5 0
3 years ago
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