I think it’s b! i hope that helps!
a/b * b/c * c/d * d/e is equal to a/e provided that b, c, d,
and e are not zero
PROVE
a/b * b/c * c/d * d/e
= (a/b *b/c) * (c/d * d/e)
= ab/bc * (c/d * d/e)
= a/c * (c/d * d/e)
= a/c * (cd/de)
= a/c * c/e
= ac/ce
= a/e
Therefore, a/b * b/c * c/d * d/e is equal to a/e provided that
b, c, d, and e are not zero
The solution is the point where the two lines intersect (are equal) so y=y and we can say:
6-x=-10-x upon adding x to both sides:
6=-10
This is never true so there is no solution to this system of equations. And for this to be true the two lines must be parallel and have different y-intercepts...
7x = -36+10x
X=12
You minus the 10 from 7 (7-10=-3) (-36/-3) gives you 12
Answer:
Kameryn will have more words typed than Joe when the number of minutes exceeds 34.
Step-by-step explanation:
Let
x -----> the number of minutes
y ----> the total words typed
we know that
<em>Kameryn</em>
-----> equation A
<em>Joe</em>
-----> equation B
Solve the system of equations by substitution
Substitute equation A in equation B and solve for x
That means
For x=34 minutes
The amount of words written by Kameryn and Joe are the same.
therefore
For x > 34 minutes
Kameryn will have more words typed than Joe when the number of minutes exceeds 34.
