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Lilit [14]
3 years ago
8

Kelly signed copies of her new book at a local book store. He had budgeted 1.15 per student. It turned out that he spent 0.25 le

ss per student. How much money did he spend for 30 student's
Mathematics
1 answer:
PolarNik [594]3 years ago
3 0

Answer:

$27

Step-by-step explanation:

In this question, we are asked to calculate how much spent on some number of students in a bookstore where books were being signed by an author. We proceed as follows:

To calculate the amount she budgeted, there are different approach we can take. We can calculate the amount she has to pay for the signing at the old price. Then, we calculate the amount of money she has to pay on discounting the fees. We then subtract the values to arrive at the total value she has spent.

Firstly, we calculate the total amount of money to be spent on the students based on his budget. He had budgeted 1.15, then the total amount budgeted would be 30 * 1.15 = $34.5

Now we are made to know that she spent 0.25 less. Thus, the total amount spent less would be 30 * 0.25 = $7.5

The actual amount thus spent is $34.5 - $7.5 = $27

He spent a total of $27 on 30 students

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Drag each tile to the correct box.
Natasha_Volkova [10]

Answer:

1) Function h

interval [3, 5]

rate of change 6

2) Function f

interval [3, 6]

rate of change 8.33

3) Function g

interval [2, 3]

rate of change 9.6

Step-by-step explanation:

we know that

To find the average rate of change, we divide the change in the output value by the change in the input value

the average rate of change is equal to

\frac{f(b)-f(a)}{b-a}

step 1

Find the average rate of change of function h(x) over interval [3,5]

Looking at the third picture (table)

f(a)=h(3)=4  

f(b)=h(5)=16

a=3

b=5

Substitute

\frac{16-4}{5-3}=6

step 2

Find the average rate of change of function f(x) over interval [3,6]

Looking at the graph

f(a)=f(3)=10  

f(b)=f(6)=35

a=3

b=6

Substitute

\frac{35-10}{6-3}=8.33

step 3

Find the average rate of change of function g(x) over interval [2,3]

we have

g(x)=\frac{1}{5}(4)^x

f(a)=g(2)=\frac{1}{5}(4)^2=\frac{16}{5}  

f(b)=g(3)=\frac{1}{5}(4)^3=\frac{64}{5}

a=2

b=3

Substitute

\frac{\frac{64}{5}-\frac{16}{5}}{3-2}=9.6

therefore

In order from least to greatest according to their average rates of change over those intervals

1) Function h

interval [3, 5]

rate of change 6

2) Function f

interval [3, 6]

rate of change 8.33

3) Function g

interval [2, 3]

rate of change 9.6

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Answer:

the answer is c

Step-by-step explanation:

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6 grams of tea: 24 fluid ounce of tea
? grams of tea: 288 fluid ounces
288×6÷24=72 grams of tea is your final answer. Hope it help!
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Answer:

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I think this is true

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Answer:

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