Looks like you did most of it.
The next step would be setting them equal to 105, like the problem suggests.
Then we can plug back in to find the numbers.
The three numbers are .
Hope this helps.
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If we graph a circle whose center is at (1, -3), the center is located at the __________ quadrant
1 answer:
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Answer:
6
Step-by-step explanation:
From the Trapezoid attached :
EF = GT
FG = LA
LE = AT = 10
LA = 24 ; FG = 24
FG + EF + GT = 40
Let : EF and GT = x
FG + 2x = 40
24 + 2x = 40
2x = 40 - 24
2x = 16
x = 16 ÷ 2 = 8
Hence, EF = GT = 8
Using Pythagoras :
Opposite² = hypotenus² - Adjacent²
LF² = LE² - FE²
LF² = 10² - 8²
LF² = 100 - 64
LF² = 36
LF = √36
LF = 6
