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2 years ago

If we graph a circle whose center is at (1, -3), the center is located at the __________ quadrant

Mathematics

1 answer:

taurus [48]2 years ago

8 0

Answer:

Quadrant IV

Step-by-step explanation:

If the circle's center is located at (1, -3), then its center is located in the 4th Quadrant.

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Triangle ABC is translated according to the rule (x, y) = (x+2y-S). If the coordinates of the pre-image of point B are

Liula [17]

The coordinates of b is 1.9

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4 years ago

Write 23.061 in words.

Tasya [4]

23.061 written in words is:

twenty-three and sixty-one thousandths.

Note the decimal point.

hope this helps

4 0

3 years ago

Using the Division algorithm to find q and r such that 3662 = q·16+r , where 0 ≤ r < 16 . What if we take c = −3662 instead o

bagirrra123 [75]

Answer:

a) If c=3662 then q=228 and r=14.

b) If c=-3662, then q=-229 and r=2

Step-by-step explanation:

a) Observe that 229*16=3664, since r must be in the interval [0,16), then 229 doesn't work, but 228*16=3648 and 3662-3648=14.

Then 3662=228*16+14.

b) Observe that -228*16=-3648 and -3648-14=-3662, but r= must be positive. Then -228 doesn't work.

But observe that -229*16=-3664 and -3664+2=-3662. So -3662=-229*16+2

4 0

3 years ago

Example 5

Svetllana [295]

Answer:

1/2*6(12+x)=12*x

1/2*(72+6)=12x

36+3x=12x

36=9x

4=x

Step-by-step explanation:

Check that x=4

1/2*6(4+12)=12*4

1/2*(24+72)=48

1/2(96)=48

48=48

So x=4 is the correct answer

3 0

3 years ago

The sum of 2 fractions is 5/6. Their difference is 1/2. Their least common denominator is 6. The denominator of one is twice the

valentinak56 [21]

Answer:

Step-by-step explanation:

Alright, lets get started.

Suppose the first fraction is : $\frac{a}{b}$

Suppose the second fraction is : $\frac{c}{d}$

The sum of both fraction is given as : $\frac{5}{6}$

$\frac{a}{b}+\frac{c}{d}=\frac{5}{6}$ .......................equation (1)

The difference of both fraction is given as : $\frac{1}{2}$

$\frac{a}{b}-\frac{c}{d}=\frac{1}{2}$ .........................equation (2)

Adding equation (1) and equation (2)

$\frac{c}{d} \ will \ be \ cancelled$

$\frac{2a}{b}=\frac{5}{6}+\frac{1}{2}$

making common denominator

$\frac{2a}{b}=\frac{5}{6}+ \frac{3}{6}$

$\frac{2a}{b}=\frac{8}{6}$

Hence,

$\frac{a}{b}=\frac{2}{3}$

Plugging the value of $\frac{a}{b}$ in equation (1)

$\frac{2}{3}+\frac{c}{d}=\frac{5}{6}$

Subtracting $\frac{2}{3}$ in both sides

$\frac{c}{d}=\frac{5}{6}-\frac{2}{3}$

$\frac{c}{d}=\frac{1}{6}$

Hence both fractions are $\frac{2}{3} \ and \ \frac{1}{6}$ ...................Answer

Hope it will help :)

7 0

3 years ago