Listing the data from the Stem and Leaves table as raw data we have:
02, 03, 03, 07, 10, 10, 17, 34, 34, 35, 35
Hence the smallest value is 02 = 2
Answer: A
Tangent 45 = height / 3
height = 3 * tan (45)
height = 3 * 1
height = 3
<span>Trapezoid area = ((sum of the bases) ÷ 2) • height
</span>
<span>Trapezoid area = (9 + 15) /2 * height
</span><span>Trapezoid area = 12 * 3
</span><span>Trapezoid area = 36
</span>
Answer:
We accept H₀. We do not have argument to keep the claim that the mean breaking strength has increased
Step-by-step explanation:
Normal Distribution
Population Mean μ₀ = 1850 pounds
Standard Deviation σ = 90 pounds
Type of test
Null Hypothesis H₀ ⇒ μ = μ₀
Alternative Hypothesis Hₐ ⇒ μ > μ₀
A one tail test (right)
n = 21 as n < 30 we use t-student table
degree of fredom 20
t = 2.845
Sample mean μ = 1893
Then, we compute t statistics
t(s) = [ 1893 - 1850 ] / 90/ √n
t(s) = 43 * 4,583 / 90
t(s) = 197,069 / 90
t(s) = 2,190
And we compare t and t(s)
t(s) = 2.190
t = 2.845
Then t(s) < t
We are in the acceptance zone, we accept H₀
