Answer:
a) 0.06 = 6% probability that a person has both type O blood and the Rh- factor.
b) 0.94 = 94% probability that a person does NOT have both type O blood and the Rh- factor.
Step-by-step explanation:
I am going to solve this question treating these events as Venn probabilities.
I am going to say that:
Event A: Person has type A blood.
Event B: Person has Rh- factor.
43% of people have type O blood
This means that 
15% of people have Rh- factor
This means that 
52% of people have type O or Rh- factor.
This means that 
a. Find the probability that a person has both type O blood and the Rh- factor.
This is

With what we have

0.06 = 6% probability that a person has both type O blood and the Rh- factor.
b. Find the probability that a person does NOT have both type O blood and the Rh- factor.
1 - 0.06 = 0.94
0.94 = 94% probability that a person does NOT have both type O blood and the Rh- factor.
Answer:
$13.20
Step-by-step explanation:
total cost of tickets = $92.40
total number of tickets = 7
cost of each ticket
= total cost of tickets ÷ total number of tickets
= 92.40 ÷ 7
= $13.20
hope this helps
It seems like you've begun to apply the grouping method.
Because the two binomials in the parentheses are the same, we can rewrite this as
(5ab-4)(x+6)
(x+6) cannot be further factored. (5ab-4) cannot be further factored either.
Final answer: (5ab-4)(x+6)
Answer:
63 cm^2
Step-by-step explanation:
p = l + w + l + w
32 = 2l + 2w
32 = 2(w + 2) + 2w
32 = 2w + 4 + 2w
32 = 4w + 4
28 = 4w
7 = w
l = w + 2
l = 7 + 2
l = 9
Check your work:
32 = 9 + 7 + 9 + 7
32 = 32
Correct
A = l × w
A = 9 × 7
A = 63
Answer:
Pfffft only one. I went to California
Step-by-step explanation: