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Nady [450]
3 years ago
15

During a windstorm, part of the top of a flagpole breaks off. The broken top portion touches the ground at an angle of 65degrees

14feet from its base.
How tall was the pole before the windstorm? Round your answer to one decimal place. Can someone answer this please
Mathematics
1 answer:
Sholpan [36]3 years ago
5 0
The situation in the problem creates a right triangle with a base of 14ft. An angle of 65 degrees means that the triangles has...

A hypotenuse of hyp = \frac{14ft}{cos(45)} = 33.13ft, representing the length of the broken part of the pole.

An opposite of sin(65)*hyp = sin(65)*33.1ft = 30.0ft, representing the height of the part of the flag that still stands.

The total original flag height is the sum of the two parts.
h = 30.0ft + 33.13ft = 63.13ft
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1)A System of equations is shown below . What is the solution to the system of equations? 5x+2y=-15 2x-2y=-6
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Answer:

x= -3 and y= 0

Step-by-step explanation:

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This can be solved with the help of matrices

In matrix form the above equations can be written in the form

\left[\begin{array}{ccc}5&2\\2&-2\/\end{array}\right]  \left[\begin{array}{ccc}x\\y\\\end{array}\right]  = \left[\begin{array}{ccc}-15\\-6\\\end{array}\right]

Let

\left[\begin{array}{ccc}5&2\\2&-2\/\end{array}\right] = A  \left[\begin{array}{ccc}x\\y\\\end{array}\right]  = X  and  \left[\begin{array}{ccc}-15\\-6\\\end{array}\right]= B

Then AX= B

or X= A⁻¹ B

where  A⁻¹= adj A/ ║A║   where mod A≠ 0

adj A=  \left[\begin{array}{ccc}-2&-2\\-2&5\/\end{array}\right]

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X= A⁻¹ B

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