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Mathematics

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NeX [460]3 years ago

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It’s BBBBBB all the way

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$
1.
(2^{x} -2^{-x})^{2} = 4^{2} \\ \\2^{2x}-2*2^{x}*2^{-x} + 2^{-2x} =4^{2} \\ \\2^{2x}-2*2^{x-x} + 2^{-2x} =4^{2} \\ \\ 2^{2x}+ 2^{-2x} - 2=16 \\ \\ 2^{2x}+ 2^{-2x} = 18

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$\\ \\ ( 2^{x})^{3} - (2^{-x})^{3} =(4)((18)+1)= 76
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