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Assoli18 [71]
3 years ago
6

Need help first to answer gets brainliest

Mathematics
1 answer:
NeX [460]3 years ago
4 0
It’s BBBBBB all the way
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a parallelogram has a base of 3 feet and a height of 5 feet. The base and height will each be doubled. Will the area also be dou
navik [9.2K]

Answer:

No, doubling the base and height would actually quadruple the area,

Step-by-step explanation:

With the original measurements of b = 3 ft and h = 5 ft,

<em>b x h = A</em>

<em>(3) x (5) = </em><em>15 ft</em>

So lets say we <em>doubled</em> the factors:

<em>(2)(3) x (2)(5) = A</em>

We would end up with 60 feet, four times that of 15.

<em>(6) x (10) = </em><em>60 ft</em>

3 0
3 years ago
A Survey of 85 company employees shows that the mean length of the Christmas vacation was 4.5 days, with a standard deviation of
GenaCL600 [577]

Answer:

The 95% confidence interval for the population's mean length of vacation, in days, is (4.24, 4.76).

The 92% confidence interval for the population's mean length of vacation, in days, is (4.27, 4.73).

Step-by-step explanation:

We have the standard deviations for the sample, which means that the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 85 - 1 = 84

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 84 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.95}{2} = 0.975. So we have T = 1.989.

The margin of error is:

M = T\frac{s}{\sqrt{n}} = 1.989\frac{1.2}{\sqrt{85}} = 0.26

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 4.5 - 0.26 = 4.24 days

The upper end of the interval is the sample mean added to M. So it is 4.5 + 0.26 = 4.76 days

The 95% confidence interval for the population's mean length of vacation, in days, is (4.24, 4.76).

92% confidence interval:

Following the sample logic, the critical value is 1.772. So

M = T\frac{s}{\sqrt{n}} = 1.772\frac{1.2}{\sqrt{85}} = 0.23

The lower end of the interval is the sample mean subtracted by M. So it is 4.5 - 0.23 = 4.27 days

The upper end of the interval is the sample mean added to M. So it is 4.5 + 0.23 = 4.73 days

The 92% confidence interval for the population's mean length of vacation, in days, is (4.27, 4.73).

8 0
3 years ago
Find the slope of the line that passes through (9,-3) and (9,-8)
miskamm [114]

Answer:

The line has no slope. I hope this helps

7 0
2 years ago
Help me again lol im not smart
Artyom0805 [142]
One could be |x|<-2
This could be one since no matter what you put in for x, it will always be positive.
6 0
3 years ago
Taryn is shopping for a Christmas tree. At Home Depot the one she likes is $149.00 and she has a 15% off coupon. At Lowe's the o
Vitek1552 [10]

Answer:

Step-by-step explanation:

At home depot

Price of Christmas tree = $149.00

Discount = 15%

Amount discounted = 15% of $149

Amount discounted = 15/100 * $149

Amount discounted = 15 * 1.49

Amount discounted = $22.35

Amount she paid = $149-$22.35

Amount she paid = $126.65

At Lowe's:

Price of Christmas tree = $175.00

Discount = 260%

Amount discounted = 20% of $175

Amount discounted = 20/100 * $175

Amount discounted = 0.2 * 175

Amount discounted = $35

Amount she paid = $175-$35

Amount she paid at Lowe's = $140

<u><em>From the prices above, it can be seen that Home Depot has a better deal since the price after removing discount is lower than that of Lowe's.</em></u>

<u><em></em></u>

<u><em>Amount she will save will be $140 - $126.65 = $13.35</em></u>

6 0
3 years ago
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