When was the case of Marbury v. Maddison
2 answers:
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Answer:
x = 11.02 inch by y = 7.35 inch
Explanation:
Let the width of the print be = x
Then the width of the page is x + (1.5+1.5) = x + 3
Let the height of the print be = y
Then the height of the page is y + (1+1) = y + 2
Given the area of the print is 81 square inches
That means, xy = 81
Therefore, y =
Therefore, the area of the page is
A = (x + 3)(y + 2)
= (x + 3)( + 2)
Now for least amount of paper to be used,
x = 11.02 inch
Now y =
=
= 7.35 inch
Therefore the dimensions of thr page for the least amount of paper is x = 11.02 inch by y = 7.35 inch