<u>Answer- </u>
In tossing four fair dice, the probability of getting at most one 3 is 0.86.
<u>Solution-</u>
The probability of getting at most one 3 is, either getting zero 3 or only one 3.
( ∵ xxxx )
( ∵ 3xxx, x3xx, xx3x, xxx3 )
P(Atmost one 3) = P(A) + P(B) = 0.48 + 0.38 = 0.86
Okay so for substitution, chose one of of the equations to solve for x. Let's solve for the second one. So you have 2x-8y=32.
Start by adding 8y to both sides:
2x=8y+32.
Then you have to get x by itself so you divide both sides by 2 which will give you:
x=4y+16.
Now you have:
6x-4y=36
x=4y+16 (this was 2x-8y=32)
Now, plug in the second equation to the first one. You would do so by plugging in the second equation to where you see x. You would have:
6(4y+16)-4y=36
Now, multiply the 6 with the 4y and 16. you would then have:
24y+96-4y=36.
Now, combine your like terms to get:
20y+96=36
Then subtract 96 to both sides:
20y=-60
Then divide both sides so that you have y all by itself:
y=-30!
You now have the answer for y, so now plug what you got for y into the other equation: x+4y=16:
x+4(-30)=60
Solve for x:
x-120=60
add 120 to both sides:
x=180!
so Your answer is Y=-30 and X=180
I hope this helped:)
180-98=82 so 82 degrees is the answer
The probability of 3 successes is 0.0384
<h3>How to determine the probability?</h3>
The given parameters are:
- Trials, n = 4
- Probability of success, p = 0.4
The binomial probability is represented as:
So, the probability of three successes is:
Evaluate the factors in the expression
Evaluate the combination expression
P(3) = 1 * 0.0384
Evaluate the product
P(3) = 0.0384
Hence, the probability of 3 successes is 0.0384
Read more about probability at:
brainly.com/question/25870256
#SPJ1
Answer:
The Answer Is A
Step-by-step explanation:
A=12.3
