Answer:
Sorry i dont now the answer
please help him/her
That would be 0.75:) hope this helps!
Answer:
Step-by-step explanation:
To find : Acceleration in first 15 min . Distance between two cities Average speed of journey
Solution:
Each horizontal block is 1/8 hr = 7.5 min
Each vertical block is 10 km/hr
Time Velocity km/hr
0 Min ( 0 hr) 0
15 Min (1/4 hr) 50
45 Min (3/4 hr) 50
60 MIn ( 1 hr) 100
90 Min ( 3/2 hr) 100
120 Min ( 2hr) 0
Acceleration in first 15 min (1/4 hr) = (50 - 0)/(1/4 - 0) = 50/(1/4)
= 200 km/h²
Distance between two cities
= (1/2)(0 + 50)(1/4 - 0) + 50 * (3/4 - 1/4) + (1/2)(50 + 100)(1 - 3/4) + 100 * (3/2 - 1) + (1/2)(100 + 0)(2 - 3/2)
= 25/4 + 25 + 75/4 + 50 + 25
= 125
Distance between two cities = 125 km
Average Speed of journey = 125/2 = 62.5 km/hr
Acceleration in first 15 min = 200 km/h²
Distance between two cities = 125 km
Average Speed of journey = 62.5 km/hr
Hope this helps..
Answer:
210
Step-by-step explanation:
first I took 120 and divided by four to show how many cupcakes he can make in thirty minutes (.5 of an hour). this was 30. the reason we divided by four is because in two hours theres four halves.
120÷4=30 for half an hour
30x2=60 this is how many cupcakes he can make in one hour
since we already know how many he makes in two hours we're going to use that
120+60=180 (three hours)
120+60=180 (three hours)180+30 (half an hour) =210
U: -2,-2
B: -5, 0
K: -5, -3
Y: -4, -3
I believe so..
