Answer:
The distance between the ship at N 25°E and the lighthouse would be 7.26 miles.
Step-by-step explanation:
The question is incomplete. The complete question should be
The bearing of a lighthouse from a ship is N 37° E. The ship sails 2.5 miles further towards the south. The new bearing is N 25°E. What is the distance between the lighthouse and the ship at the new location?
Given the initial bearing of a lighthouse from the ship is N 37° E. So,
is 37°. We can see from the diagram that
would be
143°.
Also, the new bearing is N 25°E. So,
would be 25°.
Now we can find
. As the sum of the internal angle of a triangle is 180°.

Also, it was given that ship sails 2.5 miles from N 37° E to N 25°E. We can see from the diagram that this distance would be our BC.
And let us assume the distance between the lighthouse and the ship at N 25°E is 
We can apply the sine rule now.

So, the distance between the ship at N 25°E and the lighthouse is 7.26 miles.
-20+1= -19
-19/2= -9.5
Check:
-9.5x2= -19
-19-1= -20
3
The 3 is the gradient in front of the x
Mark brainliest please
Usually, rugs have a rectangular shape, therefore the section of the living room that Patrick wants to cover is a rectangle.
The area of a rectangle can be found by multiplying the length and the width of the rectangle:
A = l × w
Hence, the most appropriate measurements Patrick should provide are the length and the width of the section of his living room he wants to cover.