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Strike441 [17]
3 years ago
13

A farmer needs to buy fencing to go around his garden. The garden is a 20’ by 15’ rectangle. How much fencing will he need

Mathematics
1 answer:
lukranit [14]3 years ago
6 0
Use sod six itch yah onto
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Type nae nae for 5 marks
baherus [9]

Answer:

nae nae

Step-by-step explanation:

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3 years ago
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The scatter plot shows the number of absences in a week for classes of different sizes. Trevor concluded that there is a positiv
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This is right the answer is A.
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2 years ago
Mason says that (12x + 4) - (-3x + 5) and 15x - 1 are equivalent. Is he correct? Explain
julia-pushkina [17]

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Yes

Step-by-step explanation:

12x minus -3x is the same as adding two positives. That gives us 15x. 4 - 5 is -1. Putting the two simplified parts of the expression together, we get 15x - 1. Mason is correct.

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3 years ago
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Please let me know ASAP
aksik [14]

Answer:

∠ BAC = 80°

Step-by-step explanation:

The sum of the interior angles of quadrilateral ACDB = 360°

DB and DC are tangents to the circle, thus

∠ DBA = ∠ ACD = 90° ( angle between tangent/ circle at point of contact )

Thus

∠ BAC + 90° + 90° + 100° = 360°

∠ BAC + 280° = 360° ( subtract 280° from both sides )

∠ BAC = 80°

4 0
3 years ago
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The area of the shaded segment is 100cm^2. Calculate the value of r.
Reil [10]
Hello, 

The formula for finding the area of a circular region is: A=  \frac{ \alpha *r^{2} }{2}

then:
A_{1} = \frac{80*r^{2} }{2}

With the two radius it is formed an isosceles triangle, so, we must obtain its area, but first we obtain the height and the base.

cos(40)= \frac{h}{r}  \\  \\ h= r*cos(40)\\ \\ \\ sen(40)= \frac{b}{r} \\ \\ b=r*sen(40)

Now we can find its area:
A_{2}=2* \frac{b*h}{2}  \\  \\ A_{2}= [r*sen(40)][r*cos(40)]\\  \\A_{2}= r^{2}*sen(40)*cos(40)

The subtraction of the two areas is 100cm^2, then:

A_{1}-A_{2}=100cm^{2} \\ (40*r^{2})-(r^{2}*sen(40)*cos(40) )=100cm^{2} \\ 39.51r^{2}=100cm^{2} \\ r^{2}=2.53cm^{2} \\ r=1.59cm

Answer: r= 1.59cm
7 0
2 years ago
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