Number of tiguers: x + 2
Number of Lions: x
Number of bears:(x+2)+1=(x+3)
We can suggest this equation:
(x+2) + (x)+(x+3)=20
3x+5=20
3x=20-5
3x=15
x=15/3
x=5.
Therefore:
Number of tiguers: x + 2=5+2=7
Number of Lions: x=5
Number of bears:(x+2)+1=(x+3)=5+3=8.
Answer: there are 7 tiguers, 5 lions and 8 bears.
A person eating at a cafeteria must choose 4 of the 13 vegetables on offer. calculate the number of elements in the sample space for this experiment.
Answer: The number of elements in the sample space for this experiment can be found using the combination formula because the order does not matter here.
Therefore, the number of elements in the sample space for this experiment is:




Therefore, the number of elements in the sample space for this experiment is 715.
Answer:
6 divided by 6 would be 0:
7/0 = 7
Your answer is 7
Because ABCD is an isosceles trapezoid, the angles A and D are congruent.
BA and CD are congruent (given) and AD is congruent to itself (reflexive property).
Then triangles BAD and CDA form a pair of SAS triangles, so they are congruent.
BD and CA are corresponding parts in those triangles, so they are congruent (CPCTC).
Answer:
D
Step-by-step explanation:
First find the probability using the normal distirbution formula X - mean / standard deviation for both X = 350 and X =450 to get the values -1 and 1 so thi(-1) < P(Z) < thi(1) if you are familiar with normal distirbution table values you will calculate that the overall probability is 0.6827
knowing this we can roughly expect how much emergencies are in the response times by 0.6827 x 144 = 98