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almond37 [142]
3 years ago
5

Given that (5,6) is on the graph of f(x), find the corresponding point for the function 4f(x)

Mathematics
1 answer:
Anvisha [2.4K]3 years ago
4 0

Answer:

The corresponding point for the function 4f(x) is (5 , 24)

Step-by-step explanation:

* Lets revise some transformation

- A vertical stretching: is the stretching of the graph away from

 the x-axis

- A vertical compression: is the squeezing of the graph toward

 the x-axis.

• if k > 1, the graph of y = k • f(x) is the graph of f (x) vertically

 stretched by multiplying each of its y-coordinates by k.

• if 0 < k < 1 (a fraction), the graph is f (x) vertically compressed

 by multiplying each of its y-coordinates by k.

* In our problem:

- Point (5 , 6) is on the graph of f(x)

- The function will be 4f(x), that means vertical stretching

 or vertical compression

∵ k = 4

∵ 4 > 1

∴ It is a vertical stretch

∴ We will multiply the y-coordinate by 4

∴ y' = 4 × 6 = 24

* The corresponding point for the function 4f(x) is (5 , 24)

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dybincka [34]

Answer:

Absolute minimum = 1.414

Absolute maximum = 2.828

Step-by-step explanation:

g(x,y)=\sqrt {x^2+y^2} \ constraints: 1\leq x\leq 2 ,\ 1\leq y\leq2

For absolute minimum we take the minimum values of x and y.

x_{minimum} =1\\y_{minimum}=1\\

Plugging in the minimum values in the function.

g(1,1)=\sqrt {1^2+1^2}\\g(1,1) = \sqrt{1+1}\\g(1,1)=\sqrt {2}\\g(1,1)=\pm 1.414\\

Absolute minimum value will be always positive.

∴ Absolute minimum = 1.414

For absolute maximum we take the maximum values of x and y.

x_{maximum} =2\\y_{maximum}=2\\

Plugging in the maximum values in the function.

g(2,2)=\sqrt {2^2+2^2}\\g(2,2) = \sqrt{4+4}\\g(2,2)=\sqrt {8}\\g(2,2)=\pm 2.828\\

Absolute maximum value will be always positive.

∴ Absolute maximum = 2.828

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3y+4x=9<br> I have to find the literal solution
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Step-by-step explanation:

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